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dimaraw [331]
4 years ago
14

Can you please answer this question

Mathematics
1 answer:
Reika [66]4 years ago
4 0
Divide 14 2/5 by 6 to determine the number of pounds each person receives.

Convert 14 2/5 into an improper fraction:   72/5.  
Divide 6 into 72/5; the result is 12/5, or 2 2/5 lb.

Each friend receives 2 2/5 lb of the pecans.
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What is the solution to the equation 3/<br> x+4+3/2x+8 = 0?
mixas84 [53]

Answer:

X= -4

Step-by-step explanation:

^ you have to isolate the radical than raise each side to the power of its index which gets you

x= -4

5 0
3 years ago
For Jane Jones is a single person with 2 exemptions. In a week she earns $212.12. Using the chart above, Jane's federal income t
SpyIntel [72]

Answer:

The other answer is INCORRECT the CORRECT answer is : 34.00

Step-by-step explanation:

In the chart it shows how much for the number of exemptions. The other answer only included one but the question asks for TWO. Therefore making it 34.00

6 0
3 years ago
Whitch of thw following is a rational number plz help as soo. As posible if not sooner
Verizon [17]

Answer:

1.425.

Step-by-step explanation:

1 .425 is the only one which can be written as a fraction ( 1425/ 1000).

π  is  a non repeating decimal which goes on without bounds.

So is √50 (try entering it on your calculator).

√-4 :  there is no real number whose square root is negative.

5 0
3 years ago
Read 2 more answers
A. Show
nydimaria [60]

a. Recall the double angle identities:

\sin^2x=\dfrac{1-\cos2x}2

\cos^2x=\dfrac{1+\cos2x}2

Then

\sin^2x\cos^2x=\dfrac{(1-\cos2x)(1+\cos2x)}4=\dfrac{1-\cos^22x}4

Applying the identity again, we have

\sin^2x\cos^2x=\dfrac{1-\frac{1+\cos4x}2}4=\dfrac{2-(1+\cos4x)}8=\dfrac{1-\cos4x}8

as required.

b. Using the result from part (a),

\sin^2x\cos^2x=\dfrac{1-\cos4x}8=\dfrac{2-\sqrt2}{16}

\implies\cos4x=\dfrac1{\sqrt2}

\implies4x=\dfrac\pi4+2n\pi\text{ or }4x=-\dfrac\pi4+2n\pi

(where n is any integer)

\implies\boxed{x=\pm\dfrac\pi{16}+\dfrac{n\pi}2}

8 0
4 years ago
Use the Pythagorean Theorem to find the missing lengths
Annette [7]

Answer:

4) c = 10

5) b = 10

6) b = 12

7) a = 4

Step-by-step explanation:

<h3>Pythagorean Theorem = a^2 + b^2 = c^2</h3>

to solve these, just substitute a, b, and c for the values given.

4) a = 8, b = 6

a^2 + b^2 = c^2

8^2 + 6^2 = c^2

64 + 36 = c^2

100 = c^2

c = \sqrt{100}

c = 10

5) a = 24, c = 26

a^2 + b^2 = c^2

24^2 + b^2 = 26^2

576 + b^2 = 676

subtract 576 from both sides

b^2 = 676 - 576

b^2 = 100

b = 10

6) a = 5, c = 13

a^2 + b^2 = c^2

5^2 + b^2 = 13^2

25 + b^2 = 169

subtract 25 from both sides

b^2 = 169 - 25

b^2 = 144

b = 12

7) b = 11, c = \sqrt{137}

a^2 + b^2 = c^2

a^2 + 11^2 = 137

a^2 + 121 = 137

a^2 = 137 - 121

a^2 = 16

a = 4

4 0
3 years ago
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