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Mashcka [7]
3 years ago
11

What is the equation of the line, in general form, that passes through point (-1, -1) and is parallel to the line whose equation

is x + y = 3?
x - y + 2 = 0
x+ y - 2 = 0
x + y + 2 = 0
Mathematics
1 answer:
lara31 [8.8K]3 years ago
3 0

ANSWER

x + y + 2 = 0

EXPLANATION

The given line passes through;

(-1,-1) and it is parallel to x + y = 3.

This line given to us can be rewritten as

y=-x+1

It has slope m=-1.

The line parallel to this line also has slope m=-1.

We obtain the equation of the line using the formula:

y-y_1=m(x-x_1)

We substitute the slope and the point to obtain:

y -  - 1 =  - 1(x -  - 1)

y + 1 =  - 1(x + 1)

y =  - x - 1 - 1

The equation of the line is

x + y + 2 = 0

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Let's prove each one:
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B) y=x+3
x=0→y=0+3→y=3 different to -3 No

C) y=4x-3
x=0→y=4(0)-3=0-3→y=-3=-3 ok
x=2→y=4(2)-3=8-3→y=5=5 ok
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x=4→y=4(4)-3=16-3→y=13=13 ok

D) y=4x+3
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