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3 years ago

The points (4,0) and (7,6) lie on a particular line. What is its equation in slope-intercept form of this line?

Mathematics

1 answer:

bulgar [2K]3 years ago

5 0

Answer:

y=2x-8

Step-by-step explanation:

To write the equation in slope intercept form y=mx+b you need a slope and the y-intercept. We will calculate the slope and then substitute it and a point into the point slope form $y-y_1=m(x-x_1)$ . Simplifying this form will result in slope intercept form.

Calculate the slope by subtracting the y values and x values of the points.

$m=\frac{6-0}{7-4} = \frac{6}{3}=2$

The slope is 2. Choose one point to use the slope with in the point slope form. Then substitute and simplify.

$y-0 = 2(x-4)\\y=2x-8$

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A spinner has three colors: red, blue, abd yellow. The red and blue sectors are the same size. If you spin twice, the probabilit

givi [52]

Answer:

36%

Step-by-step explanation:

Red and blue is 8%

and= multiply

0.08 unmultiply = 0.64 or 64%

yellow = 100-64= 36%

5 0

3 years ago

Una recta con pendiente -2 ´pasa por el punto P(5, -1). La abscisa del punto Q que está en esa recta es 1. Encuentre la ordenada

oksian1 [2.3K]

Answer:

La ordenada de Q es 7.

Step-by-step explanation:

La ecuación de una recta es:

y = a*x + b

donde a es la pendiente y b es la ordenada al origen.

Para este problema, sabemos que la pendiente es -2

Entonces:

a = -2

y = -2*x + b

También sabemos que esta recta pasa por el punto (5, -1)

Esto significa que cuando evaluamos la ecuación en x = 5, y toma el valor y = -1

Si reemplazamos esos valores en la ecuación, obtenemos:

-1 = -2*5 + b

-1 = -10 + b

-1 + 10 = b

9 = b

Entonces la ecuación de la recta es:

y = -2*x + 9

Sabemos que el punto Q está en la línea, y la abscisa de este punto es 1.

Entonces este punto es Q (1, k)

donde k es la ordenada de este punto.

Porque nuestra línea también pasa por este punto, podemos concluir que cuando x = 1, y = k

Reemplazando eso en la ecuación tenemos:

k = -2*1 + 9 = -2 + 9 = 7

k = 7

La ordenada de Q es 7.

7 0

3 years ago

What is the slope of the line shown below?

Sergio039 [100]

Answer:

Option D

Step-by-step explanation:

We are given the two points of (5, 11) and (-5, -1).

Use the slope formula.

$m=\frac{rise}{run}=\frac{-1-11}{-5-5} =\frac{-12}{-10} =\boxed{\frac{6}{5}}$

The correct option should be Option D.

Hope this helps you.

7 0

3 years ago

In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

Sidana [21]

Step 1

Find the value of TS

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

$\frac{TR}{TP} =\frac{TS}{QT}$

solve for TS

$TS =\frac{TR*QT}{TP}$

we have

$RP=2\ cm\\TP=18\ cm\\QT=27\ cm$

$TR=TP+RP\\TR=18+2=20\ cm$

substitute

$TS =\frac{20*27}{18}$

$TS =30\ cm$

Step 2

Find the value of SQ

we know that

$SQ=TS-QT$

we have

$TS =30\ cm$

$QT=27\ cm$

substitute

$SQ=30\ cm-27\ cm=3\ cm$

therefore

the answer is

the value of SQ is $3\ cm$

6 0

3 years ago

Read 2 more answers

How to solve this one

ivolga24 [154]

The x,y = -6, -5. Hope this helped, and have a great day! :D

6 0

3 years ago