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Anestetic [448]
4 years ago
11

The Pyramid of Khafre measured 143.5

Mathematics
1 answer:
nadezda [96]4 years ago
6 0

Answer:

what are the answers that are given

Step-by-step explanation:

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Solve the system 2x + 2y = −6 and 3x − 2y = 11 by using graph paper or graphing technology. What is the solution to the system?
n200080 [17]
In equation 1, When x = 0, y = -3 ( 0, -3) And when y = 0, x = -3....( 3,0) In equation 2, when x = 1, y = -4(1,-4) and when y = 2, x = 5....(5,2) You have to plot the points on graph paper and the solutions are where the two lines intersect. You can use any points for x and y.
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3 years ago
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True or False.
melamori03 [73]

Answer:

um true

Step-by-step explanation:

7 0
3 years ago
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What inequality is on the number line?​
Elis [28]
Answer:
y ≥ -5

Explanation:
y is greater than -5 because the darkened line is heading towards the positive side.
(The positives are greater than the negatives.)
(The smaller negative numbers are greater than the larger negative numbers.)
7 0
3 years ago
X6-6x3 5=0 solucion por favor
PSYCHO15rus [73]
I hope this helps you

4 0
4 years ago
Help please!What is the x-intercept of the line?X=33 Y=-22X=52 Y=-33X=71 Y=-44
tekilochka [14]

x intercept is -5

Explanation

Step 1

find the slope of the line:

when you know 2 points of the line, you can find the slope, by using:

\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}

then,Let

P1(33,-22)

P2(52,-33)

replace,

\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-33-(-22)}{52-33}=\frac{-33+22}{19}=\frac{-11}{19} \\ \text{slope}=-\frac{11}{19} \end{gathered}

Step 2

find the equation of the line

y-y_1=slope(x-x_1)\rightarrow equation

let

\begin{gathered} \text{slope}=-\frac{11}{19} \\ P1(33,-22) \end{gathered}

replace,

\begin{gathered} y-y_1=slope(x-x_1)\rightarrow equation \\ y-(-22)=-\frac{11}{19}(x-33) \\ y+22=-\frac{11}{19}x+\frac{363}{19} \\ to\text{ isolate y, subtract 22 in both sides} \\ y+22-22=-\frac{11}{19}x+\frac{363}{19}-22 \\ y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \end{gathered}

now, we have the equation of the line, to get the x intercetp ( it is when y=0)

replace

\begin{gathered} y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \\ 0=-\frac{11}{19}x-\frac{55}{19} \\ \text{isolate x} \\ \frac{11}{19}x=-\frac{55}{19} \\ 11x=-\frac{55\cdot19}{19} \\ 11x=-55 \\ \text{divide both sides by 11} \\ \frac{11x}{11}=\frac{-55}{11} \\ x=-5 \end{gathered}

so, the x intercetp is -5.

I hope this helps you

6 0
1 year ago
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