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Gnoma [55]
3 years ago
14

May types 125 words 7.5 minutes.Josh types 65 words in 3mins.Tyler types 400 words in 28 minutes. Order the student from who can

type the fastest
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0
Tyler can type the fastest among the three.
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Use the formula C = 2πr and π= 3.14 to find the circumference of a circle with a radius of 5 meters.
professor190 [17]
Solution D 

Just put into a calculator 

Hope I helped :)

7 0
4 years ago
15/30 = n/34 round to the nearest tenth.
avanturin [10]
The equation given in the question has to be answered to the nearest tenth. The only thing that one should be careful about is the cross multiplication part. Other than that there is no difficulty in the given problem. Now let us get down to the equation in the question.
15/30 = n/34
30 * n = 15 * 34
30n = 510
n = 510/30
   = 51/3
   = 17
So the value of the unknown variable "n" comes out to be 17.
6 0
3 years ago
Read 2 more answers
To find 10, Beau found 32 = 9 and 42 = 16. He said that since 10 is between 9 and 16, 10 is between 3
AlexFokin [52]

Given that:

Consider it is \sqrt{10} instead of 10 on two places.

\sqrt{10} is between 3  and 4. So, Beau thinks a good estimate for \sqrt{10} is = 3.5.

Solution:

To find \sqrt{10}, Beau found 3² = 9 and 4² = 16.

He said that since 10 is between 9 and 16.

Since 10 is close to 9, therefore \sqrt{10} must be close to 3. So, Beau's estimate is high.

Now,

(3.1)^2=9.61

(3.2)^2=10.24

Since, 10 lies between 9.61 and 10.24, therefore \sqrt{10} must be lies between 3.1 and 3.2.

\dfrac{3.1+3.2}{2}=3.15

Therefore, the estimated value of \sqrt{10} is 3.15.

4 0
3 years ago
10 POINTS! PLEASE HELP!! The illustration shows a compact disc tray that holds five CDs. The radius of each compact disc is 9 cm
MariettaO [177]

We can see that there are 5 CDs, each of radius 9 cm

<u>Area occupied by 1 disc:</u>

Area of a circle = πr²

Area of disc = π(9)²

Area of disc = 3.14 * 81 = 254 cm²

<u>Area occupied by 5 discs:</u>

Area occupied by 5 discs = Area occupied by 1 disc * 5

Area occupied by 5 discs = 254 * 5

Area occupied by 5 discs = 1270 cm²

3 0
3 years ago
What are the typical null and alternate hypotheses for a significance test on slope?
Tju [1.3M]
I'm sure you should look it up on Google I'm pretty sure that that would help you more than this stupid app OK look it up on Google or a Siri it will help you a lot better
8 0
3 years ago
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