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uysha [10]
3 years ago
6

Which equation is equivalent to

Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

a

Step-by-step explanation:

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WILL GIVE BRAINEST write at least three sentences describing what kind of rewards I look for in friendships
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Answer:

When I am looking for a for a friendship I want this person to bring out the best in me. I want them to be somebody who pushes me to live up to my full potential. The biggest reward I could get out of a friendship is having someone who I know i can lean on and the fact that they have my back if i ever need them.

Step-by-step explanation:


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4 years ago
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What is the measure of ∠R ? Round your final answer to the nearest tenth, if necessary.
Lesechka [4]

In this question, it is given that

The measure of angle Q is 96 degrees. The length of side P Q is 30 feet. The length of side R P is 54 feet.

And to find the measurement of angle R, we have to use sine law, which is

\frac{sin Q}{PR} = \frac{sin R}{PQ}

Substituting the given values,we will get

\frac{sin96}{54} = \frac{sin R}{30}

sin R = \frac{30 sin 96}{54}

R = sin^{-1}( \frac{30 sin 96}{54})
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Correct option is the second option .

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4 years ago
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Given that y = (e^x)/x, x > 0, find the range of values of x where y is a decreasing
vodka [1.7K]

Answer:

The interval for which <em>y</em> is a decreasing function of <em>x</em> is:

(0, 1)

Or as an inequality:

0

Step-by-step explanation:

We are given the equation:

\displaystyle y=\frac{e^x}{x}\, ,x>0

And we want to find the range of values <em>x</em> for which <em>y</em> is a decreasing function of <em>x</em>.

<em>y</em> is decreasing whenever <em>y'</em> is negative. Find <em>y'</em> using the Quotient Rule:

\displaystyle y'=\frac{(e^x)'(x)-e^x(x)'}{(x)^2}

Differentiate:

\displaystyle y'=\frac{xe^x-e^x}{x^2}

<em>y</em> is decreasing whenever <em>y'</em> is negative. Thus:

\displaystyle 0>\frac{xe^x-e^x}{x^2}

Multiply both sides by <em>x²</em>. This is always positive so we do not need to change the sign:

xe^x-e^x

Factor:

e^x(x-1)

e<em>ˣ</em> is always positive. So:

x-1

Adding one to both sides produces:

x

Therefore, <em>y</em> is a decreasing function of <em>x</em> when <em>x</em> is less than one (and greater than 0).

In interval notation:

(0, 1)

Or as an inequality:

0

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