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lys-0071 [83]
3 years ago
8

Caleb placed 5 beehives for every 2 acres on the peach 8 beehives for

Mathematics
2 answers:
sdas [7]3 years ago
3 0
8 beehives for every 3.25 acres
ankoles [38]3 years ago
3 0
8 beehives for every 3.25 acres
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(I have a deadline in 3 hours :c ) Ann's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs
max2010maxim [7]
A=3B
4.35A+5.40B=780.95
Substitute 3B into A for the second equation:
4.35(3B)+5.40B=780.90
13.05B+5.40B=780.90
18.45B=780.90
B=42.33
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A=3B
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3 years ago
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For questions 1-2 identify the zeros of the function
Ipatiy [6.2K]

Answer:

Step-by-step explanation:

The zeros of a function are where it crosses the x axis, so just find the coordinates for the x intercepts.

1.

(2,0) and (-1,0)

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8 0
3 years ago
N - 4 = 3n + 6<br> Plz help me if possible no pics
levacccp [35]

Answer:

n=−5

Step-by-step explanation:

n−4−3n=3n+6−3n

−2n−4=6

Step 2: Add 4 to both sides.

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Step 3: Divide both sides by -2.

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4 0
3 years ago
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Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

7 0
3 years ago
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