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lara [203]
2 years ago
9

How to find area of a square room if it's length is 5cm​

Mathematics
1 answer:
alina1380 [7]2 years ago
6 0

Answer:

150 cm²

Step-by-step explanation:

Since the room is square, assuming that it is a cube, the area will be 6s², where s is the side length.

Given a side length of 5cm, the area is

6(5)² = 6cm × 25cm = 150cm²

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Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)
LenaWriter [7]

Answer:

The slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the points

  • (-1, -2)
  • (3, 4)

Determining the slope between (-1, -2) and (3, 4)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)

m=\frac{4-\left(-2\right)}{3-\left(-1\right)}

m=\frac{3}{2}

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

4=\frac{3}{2}\left(3\right)+b

switch sides

\frac{3}{2}\left(3\right)+b=4

\frac{9}{2}+b=4

subtract 9/2 from both sides

\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}

b=-\frac{1}{2}

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)

y=\:\frac{3}{2}x\:-\frac{1}{2}

Therefore, the slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}
8 0
2 years ago
What problem types can be solved using law of sines?
aev [14]
Let's take a triangle ABC, with a, b, and c the sides length, he law of sine is:

a/sin A =b/sin B = c/sin C
If we know the value of 2 angles and one side or the value of 2 sides and one angle, we can calculate all the elements of the triangle
6 0
3 years ago
Read 2 more answers
3x +y = –15<br> -3x - 4y = 30<br> Which variable will eliminate in the system?
Anestetic [448]

Answer:

x should be eliminated

hope it helps

5 0
2 years ago
Consider the figure.<br> What is JL?
lisov135 [29]

The answer for the above mentioned problem is JL = 12.5

Step by step explanation:

Given:

JM = 8

KM = 6

To Find:

JL = ?

Formula to be used:

KM^2 = JM x ML

In order to find " JL" we must first find "ML",

KM^2 = JM x ML

         6^2 = 8 x ML

         36 = 8 x ML

         36/8 = ML

         ML = 4.5

Now JL = 4.5+8

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Thus the value of JL = 12.5

3 0
3 years ago
I need help with this problem I didn't really pay that much attention to this part of the subject.​
Flauer [41]

To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.

So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to

\log(3\cdot 3)=\log(9)

Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to

(4-3)\log(9)=\log(9)

So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.

4 0
3 years ago
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