Area = 91 in²
Step-by-step explanation:
Hope it helps you!
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
<u>x = 39</u>
Step-by-step explanation:
Let's recall that the interior angles of a triangle always add up to 180 degrees.
Upon saying that, we have:
102 + 39 + x = 180
x = 180 - 102 - 39
x = 39
<u>The value of x is 39 degrees</u>
Answer: The area that it covers is 78.53 square meters
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Area of a circle (A): π r²
Where:
r = radius (in our case is 5 meters)
So, replacing with the values given:
A= π (5)² = π 25 =78.53 square meters
In conclusion, the area that it covers is 78.53 square meters
Feel free to ask for more if needed or if you did not understand something.
