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spayn [35]
4 years ago
7

I need help!?????????

Mathematics
1 answer:
Lorico [155]4 years ago
7 0
Use photomath app. U can solve all those problem with that app. 

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Solve for x: x/3= 7<br><br> x= 21<br> x= 12<br> x= 7/3<br> x= 11
myrzilka [38]

Answer:

7÷3=2 1/3...

×=7/3...

4 0
3 years ago
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Determine if the triangles, ΔSXC and ΔDXY, are similar. If so, identify the similarity criterion.
Lesechka [4]
THE ANSWER IS B SAS SIMILARITY
3 0
4 years ago
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Can you give me the anwsers fast pls
Yakvenalex [24]

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false true false true

Step-by-step explanation:

4 0
3 years ago
Complete the equation so that it has solutions of –5 and 7.<br> +<br> = 0
nekit [7.7K]

Answer:

the answer is - 2

Step-by-step explanation:

7-5=2-2=0

8 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
Read 2 more answers
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