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Vsevolod [243]
3 years ago
5

What are the solutions to the following system of equations? y=x^2+12x+30 and 8x-y=10

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side.  To do this, add -8x+10 to both sides.  Then 0 = x^2 +4x +40.  You must now solve this quadratic equation for x, if possible.  I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10  and  x^2+12x+30 on the same screen.  You will see two separate graphs that do NOT intersect.  This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
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3 years ago
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julia-pushkina [17]

Answer:

Step-by-step explanation:

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Elina [12.6K]
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5 0
3 years ago
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Ber [7]

Answer:

$45.15

Step-by-step explanation:

When you are dealing with questions with percents in them—like this one—you have to turn the percent into a decimal. To make 7.5% into a decimal, you move the decimal point 2 spaces to the left. So, 7.5% is also 0.075.

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