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3 years ago

What are the solutions to the following system of equations? y=x^2+12x+30 and 8x-y=10

1 answer:

6 0

Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.

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Given g(x)=-x-1, find g(-4)

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Answer:

g(-4)=3

Step-by-step explanation:

g(x)=-x-1

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sammy [17]

Answer:

4. 1/25

5. 1/16

6. 2/9

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Step-by-step explanation:

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3 years ago

Which graph represents the function y = 2x – 4? A coordinate plane with a line passing through (negative 4, 0) and (0, 2). A coo

VARVARA [1.3K]

Answer:

The third option: "A coordinate plane with a line passing through (0, negative 4) and (2, 0)."

Step-by-step explanation:

Use the equation defined by the function: y = 2x - 4 to check the (x, y) values they give you. If they both render true mathematical statements, those are indeed points on the plane that belong to the given line.

For the third case; the pairs (0,-4) and (2,0), both satisfy the equation of the line that is given.

For (0,-4): y = 2x - 4 becomes:

$(-4)=2(0)-4\\-4=0-4\\-4=-4$ which is a TRUE statement

For (2,0): y = 2x - 4 becomes:

$(0)=2(2)-4\\0=4-4\\0=0$ which is also a TRUE statement.

This option is the only one that verifies both given points as truly being part of the given line.

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Dahasolnce [82]

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3 years ago