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3 years ago

Is c+3/5=15 an identity

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

No, becuase c has to be a certain number to equal 15

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Write the equation of this circle in standard form

Svetradugi [14.3K]

Answer:

Standard equation of this circle is (x +5)² + y² = 9.

Step-by-step explanation:

The equation of a circle with center at (h,k) and a radius of r is:

(x - h)² + (y - k)² = r²

Subtitute the variables with h= -5, k = 0, and r = 3

(x - (-5))² + (y - 0)² =3²

(x + 5)² + y² = 9

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8 0

3 years ago

A balance sheet shows beginning values of $56,300 for current liabilities and$289,200 for long-term debt. The ending values are

Black_prince [1.1K]

Answer:

The amount of net new borrowing is $29,200

Step-by-step explanation:

Net new borrowing =

Long term debt at the end - Long term debt at the start

= $318,400-289,200 = $29,200

7 0

3 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$