3 years ago

I’ve posted this so many times someone finish this so I can sleep and not wake up to another assignment

1 answer:

3 0

Hi! I’m not done with it yet, but I just wanted to let you know that I’m working on this for you! Please try not to stress!

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qwelly [4]

Answer:D)

Step-by-step explanation:

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3 years ago

Please Help!

Flura [38]

Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.

Therefore,
Length of train = 150 m
Speed of train = 25 m/s

8 0

3 years ago

Please help I need help

navik [9.2K]

Answer:

L=10pi, or 31.42

Step-by-step explanation:

4 0

3 years ago

ASAP!!!!!!!<br><br> y-13=4(x-2)

Juliette [100K]

Y-13=4(x-2)
y-13=4x-8
y=4x+5

5 0

3 years ago

(b) If n(U)= 300, n(M) = 150, n(T) = 144 and n( MT)= 33. Find the value of n(MUT). (ii) Present the above information in a Venn

ICE Princess25 [194]

Answer:

Step-by-step explanation:

n(M ∪ T) = n(M) + n(T) - n(M∩T)

= 150 + 144 - 33

= 294 - 33

= 261

8 0

3 years ago