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alexdok [17]
3 years ago
6

suppose triangle ABC is reflected over the x-axis. If the distance between point A and the x-axis is 7, what is the distance bet

ween the x-axis and A
Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

7

Step-by-step explanation:

If A is 7 units away from the x-axis then the x-axis is seven units away from A.

That's if I read the question right.

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Ok I rlly need help with this question it’s rlly hard for me there’s a picture to show —> helppp
Whitepunk [10]

Answer:

x=20; vertical angles theorem

Step-by-step explanation:

hi! we can use the vertical angles theorem for this. vertical angles are congruent to each other, meaning they are the same amount of degrees. so, we can set 2x+10 and 50 equal to each other.

2x+10=50

2x=40

x=20

x=20 because of the vertical angles theorem.

8 0
3 years ago
A 18 foot ladder is leaning against a wall as shown
Inga [223]
I'm guessing the diagram shows a ladder leaning against a wall, making a right angle triangle with respect to the ground and the wall.

So, the wall's height is going to be the 'h', which will also be the 'opposite side' from the angle <span>ϴ which is made from the ladder and the ground.
</span>The ladder's length (18 foot) is going to be the 'hypotenuse' side and the other remaining side will be the 'adjacent'.

Now, once you've sorted out which side is which, we have to find the h (opp), and according to  SOH CAH TOA, we will choose Sin<span>ϴ = opp/hyp.
</span>so Sinϴ = h/18....now we gotta find h, so 'cross multiply' the equation to get  h = 18 x sin<span>ϴ.
</span>
To find angle ϴ, simply take the inverse of Sinϴ= h/18... and you'll get ϴ =  sin-1 (sin inverse) h/18

Hope this helps



6 0
3 years ago
Add<br>show all steps please
choli [55]
\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}    so, no breaks on the denominator thus, the LCD will be all three then.

\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}\implies \cfrac{[3x(x-1)]+[4x(x-2)]-[(x-2)(x-1)]}{x(x-2)(x-1)}&#10;\\\\\\&#10;\cfrac{[3x^2-3x]+[4x^2-8x]-[x^2-3x+2]}{x(x-2)(x-1)}&#10;\\\\\\&#10;\cfrac{3x^2-3x+4x^2-8x-x^2+3x-2}{x(x-2)(x-1)}&#10;\\\\\\&#10;\cfrac{6x^2-8x-2}{x(x-2)(x-1)}\implies \cfrac{2(x^2-4x-1)}{x(x-2)(x-1)}
3 0
4 years ago
Which relationships have the same constant of proportionality between y and x as the equation y
sdas [7]

Answer:

I'm not too good at this but I got 10/4??

Step-by-step explanation:

please let me know if I'm right!

6 0
3 years ago
Evaluate the expression when a= 2.<br> a? +27
Troyanec [42]
Since a equals 2, 2 plus 27 is equal to 29. So your answer is 29. Hope that helped:)
7 0
4 years ago
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