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matrenka [14]
3 years ago
9

Suppose f(x) = 5x - 2x... Find f(2)​

Mathematics
1 answer:
Semmy [17]3 years ago
7 0
F(2)=5(2)-2(2)
f(2)=10-4
f(2)=6
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Solve -2/3x > 8 or -2/3x < 4.
vekshin1
<h3>Answer: Choice C</h3>

{x | x < -12 or x > -6}

=========================================================

Explanation:

Let's solve the first inequality for x.

(-2/3)x > 8

-2x > 8*3

-2x > 24

x < 24/(-2)

x < -12

The inequality sign flips when we divide both sides by a negative value.

Let's do the same for the second inequality.

(-2/3)x < 4

-2x < 4*3

-2x < 12

x > 12/(-2)

x > -6

The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.

Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.

8 0
3 years ago
Ok this is hard i know but help plz edit my attachment or printtt it out and help meee plzzz
Elena L [17]

Answer:

1.)  W(2,4)  X(4,4)  Y(4,1)  Z(2,1)

2.)  Q(1,1)   R(1,-4)   S(-2,-4)

3.)  A(2,2)  B(4,1)  C(4,3)  D(2,4)

4.)  F(-2,-2)  G(4,-4)  H(2,6)

Hope this helps!!

6 0
4 years ago
Select all the points that are on the line through LaTeX: (0,5)( 0 , 5 ) and LaTeX: (2,8)( 2 , 8 ). Group of answer choices LaTe
Ivenika [448]

Answer:

The points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

Step-by-step explanation:

The equation of the line passing through two points (x_1,y_1) and (x_2,y_2) is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

So, the equation of the line passing through two points (0,5) and ( 2, 8 ) is

y-5=\frac{8-5}{2-0}(x-0)

\Rightarrow y=1.5x+5\cdots(i)

For the point (4,11), pout x=4 in equation (i), we have

y=1.5\times4 +5=11, which is given y coordinate, hence this point (4,11) lies on the line.

For the point (5,10), pout x=5 in equation (i), we have

y=1.5\times5 +5=12.5, which is not the given y coordinate, hence the point (5,10) doesn't lie on the line.

For the point (6,14), pout x=6 in equation (i), we have

y=1.5\times6 +5=14, which is the given y coordinate, hence the point (6,14)  lies on the line.

For the point (30,50), pout x=30 in equation (i), we have

y=1.5\times30 +5=50, which is the given y coordinate, hence the point (30,50) lies on the line.

For the point (40,60), pout x=40 in equation (i), we have

y=1.5\times40 +5=65, which is not the given y coordinate, hence the point (40,60) doesn't lie on the line.

Hence, the points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

4 0
3 years ago
What is the sun (2/5 x + 5/8) + (1/5 x - 1/4)
qwelly [4]

Answer:

3x/5 + 3/8

Step-by-step explanation:

3 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?\
goblinko [34]

Answer:

Option A is correct.

Solution for the given equation is,

Step-by-step explanation:

Given that : Let then our equation become; .....[1]

A quadratic equation is of the form:

.....[2] where a, b and c are coefficient and the solution is given by;

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;Simplify:or and

Simplify:y = 1 and

Substitute y = cos x we have;⇒and⇒

The solution set:  

Therefore, the solution for the given equation   is, 0 degrees

5 0
3 years ago
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