Hello,
x^2+y^2+8x-6y+21=0
Rewritten in the form of a standard circle equation:
(x-(-4))^2+(y-3)^2=2^2
Therefore, the circle properties are:
(a,b)=(-4,3),r=2
The radius of the circle whose equation is <span>x^2 + y^2 + 8x - 6y + 21 =0 is 2.
Faith xoxo</span>
Answer:
5x - 4y = 0
Step-by-step explanation:
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
given 0 = - 5x + 4y ( multiply through by - 1 )
5x - 4y = 0 ← in standard form
