<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
The correct answer is: [D]: "no real solutions" .
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The only "answers" would be: " <span>± 6i " ;
</span> → <span>both of which are not "real solutions" .
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</span>
Answer:
B 46.2
Step-by-step explanation:
Answer:
(x, y) = (- 3, 4)
Step-by-step explanation:
Given the 2 equations
5x + 2y = - 7 → (1)
4x - y = - 16 → (2)
multiply all terms in (2) by 2
8x - 2y = - 32 → (3)
Add (1) and (3) term by term
(5x + 8x) + (2y - 2y) = (- 7 - 32)
13x = - 39 ( divide both sides by 13 )
x = - 3
Substitute x = - 3 into either (1) or (2) and solve for y
substituting in (1) gives
(5 × - 3) + 2y = - 7
- 15 + 2y = - 7 ( add 15 to both sides )
2y = 8 ( divide both sides by 2 )
y = 4
solution is (- 3, 4 )
