The question says fill in the blanks I REALLY NEED HELP ASAP PLEASE

Can any negative integer be greater than a positive integer explain

Keith_Richards [23]

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

$y < 0 < x$

and since the relation of order "<" is transitive, this implies

$y < x$

5 0

3 years ago

20. What do you think would happen to the variability (standard deviation) of the distribution of sample proportions if the samp

Naya [18.7K]

Answer:

Step-by-step explanation:

Sample proportion p is the proportion of favourable numbers to total number in the sample

By central limit theorem and also approximation of binomial to normal , we have sample proportion for large number of samples will be normal

with mean = sample proportion

and std deviation = $\sqrt{\frac{pq}{n} }$

Thus we find standard deviation of proportion sample is inversely proportional to the square of the sample size n.

It follows automatically that as sample size increases std deviation decreases.

Here from 80 sample size was made to 200

So std deviation would decrease automatically

4 0

2 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

(c)43 times

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0

3 years ago

Marshall drove to work in rush hour traffic, going just 27 miles in 1 hour and 20 minutes. Later that day, he left work early to

iragen [17]

Answer:

The average speed of Marshall is 29.7 mph

Step-by-step explanation:

Given;

distance traveled to work, d₁ = 27 miles

distance traveled back home, d₂ = 27 miles

initial time taken, t₁ = 1 hour and 20 minutes

final time taken, t₂ = 29 minutes

Total distance traveled, d = d₁ + d₂ = 27 miles + 27 miles = 54 miles

Total time taken for the journey, t = t₁ + t₂ = 1 hour + ( 20 mins + 29 mins)

t = 1 hour + 49 mins = 1 hour + 0.817 hour = 1.817 hour

The average speed is given by;

v = total distance / total time

v = 54 miles / 1.817 hour

v = 29.7 mph

Therefore, the average speed of Marshall is 29.7 mph

8 0

3 years ago

Add the following matrices.

aksik [14]

Answer:

[7 6]

[7 4]

Step-by-step explanation:

4 0

2 years ago

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