Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
Answer:
Yes
Step-by-step explanation:
All rhombuses are parallelograms, but not all parallelograms are rhombuses. All squares are rhombuses, but not all rhombuses are squares. The opposite interior angles of rhombuses are congruent. Diagonals of a rhombus always bisect each other at right angles.
Subtract 33 from both sides
6x>3x+30-36x>3x+30−3
Simplify 3x+30-33x+30−3 to 3x+273x+27
6x>3x+276x>3x+27
Subtract 3x3x from both sides
6x-3x>276x−3x>27
Simplify 6x-3x6x−3x to 3x3x
3x>273x>27
Divide both sides by 3
3x>\frac{27}{3}x>
3x> 27
Simplify \frac{27}{3}
3
ANSWER: x>9
Answer:
m=1/3
Step-by-step explanation:
11m- 4/3=2m+5/3
-2m. - 2m
9m -4/3=5/3
+4/3.+ 4/3
9m= 9/3
m=1/3
Answer:
Nwm miałem to dawno powodzenia
