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mixer [17]
3 years ago
14

PLS HELP I NEED THIS DONE NOW AND PLS EXPLAIN

Mathematics
2 answers:
Yanka [14]3 years ago
8 0
Jekskejd kwneofm sir corny iqnrofm roqoe
Minchanka [31]3 years ago
4 0

Answer:

The answer is 15.

Step-by-step explanation:

Don't forget about the A and H equaling 5. That is there to throw you off. A and B equals 8. Right? Well that's the length. The the A and E is 3. Right? Well that's the height. what you do is cut the triangular prism in half and you end up with a triangular prism with a height of 5. Then you multiply that with 1.5. You get 1.5 by dividing 3 by 2.  You then get 7.5. Now multiply that with 2. Your final answer is 14.

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loris [4]
468=40x+18(x-3)
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522=58x
9=x
I'm not sure if you need to know x at all, if not, the top equation is all you need.
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The function f(x)= --x is shown on the graph.
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Answer:

Option (3).

Step-by-step explanation:

Attached figure is the graph of a function,

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Since domain of any function is the set of all possible input values of the function,

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3 years ago
Does anyone know this
Bingel [31]

Answer:

t

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In triangle fgy, side f is the shorter side adjacent to the 90 degree angle and side g is the longer side. In triangle gte, side g is the shorter side adjacent to the 90 degree angle and side t is the longer side.

6 0
3 years ago
Please help me!! 100 points!!
Lyrx [107]
Part A.

We could take, for example:

\begin{cases}x\geq-3\\y\geq3\end{cases}

For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.

Part B.

Simply, substitute x and y coordinates of D and E <span>to the system of inequalities from part A, and check if its is true, what we get.
</span>
D=(-2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}-2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}

so point D is a solution,

E=(2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}

and point E is also a solution to <span>our system of inequalities.
</span> 
Part C.

There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:

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F=(3,-4)\\\\y\ \textless \ 3x-3\quad\implies\quad-4\ \textless \ 3\cdot3-3\quad\implies\quad-4\ \textless \ 6\quad\text{True}\\\\\\

So Timothy can attend schools C and F.

We can also draw a graph of that inequality (pic 2).

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(f+g)(x) = f(x) + g(x)

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= x^2 + 2x + 2

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