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3 years ago

PLS HELP I NEED THIS DONE NOW AND PLS EXPLAIN

Mathematics

2 answers:

Yanka [14]3 years ago

8 0

Jekskejd kwneofm sir corny iqnrofm roqoe

Minchanka [31]3 years ago

4 0

Answer:

The answer is 15.

Step-by-step explanation:

Don't forget about the A and H equaling 5. That is there to throw you off. A and B equals 8. Right? Well that's the length. The the A and E is 3. Right? Well that's the height. what you do is cut the triangular prism in half and you end up with a triangular prism with a height of 5. Then you multiply that with 1.5. You get 1.5 by dividing 3 by 2. You then get 7.5. Now multiply that with 2. Your final answer is 14.

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This week, Michael collected $468 for delivering newspapers. He had 40 repeat customers and 18 new ones. As an incentive, he cha

loris [4]

468=40x+18(x-3)
468=40x+18x-54
468=58x-54
522=58x
9=x
I'm not sure if you need to know x at all, if not, the top equation is all you need.

7 0

3 years ago

Read 2 more answers

The function f(x)= --x is shown on the graph.

sertanlavr [38]

Answer:

Option (3).

Step-by-step explanation:

Attached figure is the graph of a function,

f(x) = - $\sqrt{-x}$

Since domain of any function is the set of all possible input values of the function,

Therefore, Domain of the function is,

Domain : x ≤ 0 Or (-∞, 0]

And range of the function is the set of all possible output values (y-values) of the function.

Therefore, Range of the function will be,

Range : y ≤ 0 Or (-∞, 0]

Therefore, Domain and range of this function is same.

Option (3) will be the answer.

7 0

3 years ago

Does anyone know this

Bingel [31]

Answer:

Step-by-step explanation:

In triangle fgy, side f is the shorter side adjacent to the 90 degree angle and side g is the longer side. In triangle gte, side g is the shorter side adjacent to the 90 degree angle and side t is the longer side.

6 0

3 years ago

Please help me!! 100 points!!

Lyrx [107]

Part A.

We could take, for example:

$\begin{cases}x\geq-3\\y\geq3\end{cases}$

For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.

Part B.

Simply, substitute x and y coordinates of D and E to the system of inequalities from part A, and check if its is true, what we get.

$D=(-2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}-2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}$

so point D is a solution,

$E=(2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}$

and point E is also a solution to our system of inequalities.

Part C.

There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:

$A=(-5,5)\\\\y\ \textless \ 3x-3\quad\implies\quad5\ \textless \ 3\cdot(-5)-3\quad\implies\quad5\ \textless \ -18\quad\text{False}\\\\\\
B=(-4,-2)\\\\y\ \textless \ 3x-3\quad\implies\quad-2\ \textless \ 3\cdot(-4)-3\quad\implies\quad-2\ \textless \ -15\quad\text{False}\\\\\\
C=(2,1)\\\\y\ \textless \ 3x-3\quad\implies\quad1\ \textless \ 3\cdot2-3\quad\implies\quad1\ \textless \ 3\quad\text{True}\\\\\\
D=(-2,4)\\\\y\ \textless \ 3x-3\quad\implies\quad4\ \textless \ 3\cdot(-2)-3\quad\implies\quad4\ \textless \ -9\quad\text{False}\\\\\\
E=(2,4)\\\\y\ \textless \ 3x-3\quad\implies\quad4\ \textless \ 3\cdot2-3\quad\implies\quad4\ \textless \ 3\quad\text{False}\\\\\\$

$F=(3,-4)\\\\y\ \textless \ 3x-3\quad\implies\quad-4\ \textless \ 3\cdot3-3\quad\implies\quad-4\ \textless \ 6\quad\text{True}\\\\\\$

So Timothy can attend schools C and F.

We can also draw a graph of that inequality (pic 2).

8 0

3 years ago

Read 2 more answers

Find (f+g)(x) for the function. f(x) = x2 + x g(x) = x + 2

Alexandra [31]

(f+g)(x) = f(x) + g(x)

x^2 + x + x + 2

= x^2 + 2x + 2

Final answer: x^2 + 2x + 2

3 0

3 years ago