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Serggg [28]
4 years ago
11

Sally bought apples that cost $1.95 per pound and grapes that cost $2.59 per pound.

Mathematics
2 answers:
likoan [24]4 years ago
8 0
The correct answer to this question is D
Natalka [10]4 years ago
5 0

Answer:

6

Step-by-step explanation:

pp

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Find the intercepts and the vertical and horizontal asymptotes, and then use them to sketch a graph of the function. f(x)=x+2/x^
hoa [83]

We have the function:

f(x)=x+\frac{2}{x^2}-16.

We must find:

0. the intercepts,

,

1. the vertical and horizontal asymptotes.

1) x-intercepts

The x-intercepts are given by the x values such that f(x) = 0. So we must find the values of x that satisfies the equation:

f(x)=x+\frac{2}{x^2}-16=0.

Solving for x, we get:

\begin{gathered} x+\frac{2}{x^2}-16=0 \\ x\cdot x^2+2-16\cdot x^2,\text{ }x\ne0, \\ x^3-16x^2+2=0. \end{gathered}

The real roots of this equation are:

\begin{gathered} x_1\approx15.9922, \\ x_2\approx0.35757, \\ x_3\approx-0.34975. \end{gathered}

So the x-intercepts are the points:

\begin{gathered} P_1=(15.9922,0), \\ P_2=(0.35757,0), \\ P_3=(-0.34975,0)\text{.} \end{gathered}

2) y-intercepts

The y-intercepts are given by the y values such that x = 0. Replacing x = 0 in the definition f(x), we see that the denominator of the second term diverges. So we conclude that there are no y-intercepts.

3) Vertical asymptotes

Vertical asymptotes are vertical lines near which the function grows without bound. From point 2, we know that the function grows without limit when x goes to zero. So one vertical asymptote is:

x=0.

4) Horizontal asymptotes

Horizontal asymptotes are horizontal lines that the graph of the function approaches when x → ±∞. We consider the limit of the function f(x) when x → ±∞:

\lim _{x\rightarrow\pm\infty}f(x)=\lim _{x\rightarrow\pm\infty}(x+\frac{2}{x^2}-16)\rightarrow\pm\infty.

We see that the function does not tend to any constant value when x → ±∞. So we conclude that there are no horizontal asymptotes.

5) Oblique asymptotes

When a linear asymptote is not parallel to the x- or y-axis, it is called an oblique asymptote or slant asymptote.

A function ƒ(x) is asymptotic to the straight line y = mx + n (m ≠ 0) if

{\displaystyle\lim _{x\to+\infty}\mleft[f(x)-(mx+n)\mright]=0\, {\mbox{ or }}\lim _{x\to-\infty}\mleft[f(x)-(mx+n)\mright]=0.}

We consider the line given by:

y=mx+n=x-16.

We compute the limit:

\begin{gathered} \lim _{x\rightarrow\pm\infty}(f(x)-(x-16)) \\ =\lim _{x\rightarrow\pm\infty}((x+\frac{2}{x^2}-16)-(x-16)) \\ =\lim _{x\rightarrow\pm\infty}(\frac{2}{x^2}) \\ =0. \end{gathered}

So we have proven that f(x) has the oblique asymptote:

y=x-16.

6) Graph

Plotting the intercepts and the asymptotes, we get the following graph:

Answer

1) x-intercepts: (-0.34975, 0), (0.35757, 0), (15.9922, 0)

2) y-intercepts: none

3) Vertical asymptotes: x = 0

4) Horizontal asymptotes: none

5) Oblique asympsotes: y = x -16

6) Graph

6 0
1 year ago
PLEASE HELP
liubo4ka [24]
I am so sorry I don’t know etheir I will research a litttle and come back later
6 0
3 years ago
Which statement is correct?
kondor19780726 [428]

Answer:

Correct option is (a).

Step-by-step explanation:

The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or matched-samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

We use the paired <em>t</em>-test if we have two measurements on the same item, person or thing. We should also use this test if we have two items that are being measured with a unique condition.

For instance, an experimenter tests the effect of a medicine on a group of patients before and after giving the doses.

Or in case of testing the level of reading comprehension of students before and after the speed-reading class we use t-test for dependent means.

The assumptions of paired <em>t</em>-test are:

  • The dependent variable that is tested should be continuous
  • The observations are independent
  • The dependent variable is normally distributed
  • There should not be any outliers.

Since the data consists of matched pair, both the samples must be of the same size.

Thus, the correct option is (a).

5 0
3 years ago
Could someone help me please if you don’t mind thank you so much!
Marina86 [1]

Answer:

m = 11

Step-by-step explanation:

Given

\frac{2}{5} (m + 4) = 6 ← multiply both sides by 5 to clear the fraction

2(m + 4) = 30 ( divide both sides by 2 )

m + 4 = 15 ( subtract 4 from both sides )

m = 11

This method avoids having to deal with awkward fractions

6 0
3 years ago
30 points, please help
ale4655 [162]

Answer:

Step-by-step explanation:

area 1 and 2 should be painted

4 0
2 years ago
Read 2 more answers
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