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Phoenix [80]
3 years ago
7

How would you create a perpendicular bisector to a segment AB using a unmarked straight edge compass?

Mathematics
1 answer:
AysviL [449]3 years ago
7 0
It is tedious to make a perpendicular bisector using an unmarked straightedge and an unmarked compass.
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CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!
aksik [14]

Answer:

F= 3x^2

Step-by-step explanation:

1) Multiplying exponents causes them to add, for instance if you were to multiply x^3 * x^4 the final product would be x^7. If you were to divide exponents then they would subtract.

2) Similarly in this problem  you would determine the missing factor by dividing the product from -10x^3

3)  Using the steps above, begin dividing.

-30x^5 / -10x^3

4) -30 divided by -10 is 3 and as mentioned in step number one, you subtract exponents whenever they are divided by each other.  5-3=2

5) Due to all of the steps mentioned above, The answer is 3x^2

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4 years ago
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Citizens under the age of 18 are not allowed to vote." Part A: Write an inequality to show the age of citizens who are allowed t
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The age of citizens allowed to vote is x:
x >= 18

B
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3 years ago
QUICK QUICK! 1 MINUTE ONLY PLEASE!
Gekata [30.6K]

2 laps per minute

2 laps------60 s

1 laps -----x s

x=(1*60)/2

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If 3x^2 -2x+7=0, then(x-1/3)^2=
Harman [31]
3x² - 2x + 7 = 0.

Using method of completing the square.

3x² - 2x = 0 - 7

3x² - 2x = -7          Divide through by 3.

x² - 2/3x = -7/3   ...........(d)

Coefficient of x = -2/3,  half of it = 1/2*-2/3 = -1/3    square of it = (-1/3)² = 1/9

We add (1/9) to both sides of equation (d)

<span>x² - 2/3x = -7/3 
</span>
<span>x² - 2/3x + 1/9 = -7/3 + 1/9

We factorize it by making using of half of the coefficient,  -1/3
</span>
(x - 1/3)² = -7/3 + 1/9

<span>(x - 1/3)² = -20/9
</span>
That's the answer as asked by the question.   -20/9
5 0
3 years ago
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