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3 years ago

Find the slope of the points 2,8 and 12,55

Mathematics

2 answers:

Ber [7]3 years ago

7 0

Answer:

m = 4.7

Step-by-step explanation:

If you plug in these values in the slope formula, this is what happens:)

LUCKY_DIMON [66]3 years ago

5 0

Answer:

47/10x

**Do not leave your answer as a decimal, slope is usually in fraction form**

Step-by-step explanation:

Slope Formula: $\frac{\text{rise}}{\text{run}} / \frac{y_2 - y_1}{x_2 - x_1}$ In this formula, subtract the 1st coordinate from the second. So, the 2nd y coordinate goes first, place a "minus" sign, and then the 2nd y-coordinate. This is the same for the x coordinates.

Finding the Answer: To find the answer, we just plug the numbers correctly into the equation, just as I explained above. We would do 55-8 first, which is 47, and then 12-2 which is 10.

Combined, the answer is 47/10x. You always place an x after the slope, which can be used to plug in other numbers. The answer cannot be simplified anymore, so this is simplfied.

You might be interested in

Find two numbers the exact answer is between 6x7,381

sineoko [7]

I think the answer is 210.442

5 0

3 years ago

↔ ↔

MrRissso [65]

Answer:

1. $\dfrac{4}{3}$

2. $y=6x-11$

3. $4$

Step-by-step explanation:

The equation of the line that passes trough the points A(14,-1) and B(2,1) is

$\dfrac{x-14}{2-14}=\dfrac{y-(-1)}{1-(-1)},\\ \\\dfrac{x-14}{-12}=\dfrac{y+1}{2},\\ \\y+1=-\dfrac{1}{6}(x-14),\\ \\y=-\dfrac{1}{6}x+\dfrac{7}{3}-1,\\ \\y=-\dfrac{1}{6}x+\dfrac{4}{3}.$

The y-intercept of this line is

$y=-\dfrac{1}{6}\cdot 0+\dfrac{4}{3}=\dfrac{4}{3}.$

Line BC is perpendicular to line AB, then its slope is $6.$ Line BC passes through the point B, so

$y-1=6(x-2),\\ \\y-1=6x-12,\\ \\y=6x-11.$

If the y-coordinate of point C is 13, then x-coordinate is

$13=6x-11,\\ \\6x=13+11,\\ \\6x=24,\\ \\x=4.$

7 0

4 years ago

Sandra has a rectangular pool in her backyard that is 9 feet long and 4 feet wide. A resort has a pool that is similar in shape,

grigory [225]

Answer:

? = 13.5

PLZ MARK AS BRAINLIEST

Step-by-step explanation:

6/4 = 1.5

9*1.5 = 13.5

5 0

3 years ago

Henry, a 41-year-old male, bought a $100,000, 10-year life insurance policy through his employer. Henry is paid biweekly. what i

iren2701 [21]

B)$578
The premium for a male age 41 for ten-year policy is 5.78 per 1000 of coverage. 100000/1000 = 100
100 times 5.78 = 578 annual premium.

8 0

4 years ago

1. A coin-operated drink machine was designed to discharge a mean of 7 ounces of coffee per cup. In a test of the machine, the d

Lesechka [4]

Answer:

No, at the 0.1 level of significance, there is not enough evidence to conclude that the true mean discharge, µ, differs from 7 ounces.

Step-by-step explanation:

We are given that a coin-operated drink machine was designed to discharge a mean of 7 ounces of coffee per cup. In a test of the machine, the discharge amounts in 13 randomly chosen cups of coffee from the machine were recorded.

The sample mean and the sample standard deviation were 7.08 ounces and 0.22 ounces, respectively.

Let $\mu$ = true mean discharge amount

SO, Null Hypothesis, $H_0$ : $\mu$ = 7 ounces {means that the true mean discharge, µ, does not differs from 7 ounces}

Alternate Hypothesis, $H_a$ : $\mu \neq$ 7 ounces {means that the true mean discharge, µ, differs from 7 ounces}

The test statistics that will be used here is One-sample t test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean discharge amount = 7.08 ounces

s = sample standard deviation = 0.22 ounces

n = sample of coffee cups = 13

So, test statistics = $\frac{7.08-7 }{{\frac{0.22}{\sqrt{13} } } }$ ~ $t_1_2$

= 1.311

Now at 0.1 significance level, the t table gives critical values between -1.782 and 1.782 at 12 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the the true mean discharge, µ, does not differs from 7 ounces.

5 0

3 years ago