Answer:
this assignment is for today, please help me find out the amswer
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
Statement A and C are true about the normal distribution.
Step-by-step explanation:
We have to identify true statements for normal distribution.
A) True
The mean, median and mode for a normal distribution are same
B) False
The parameters of normal distribution are mean and the standard deviation.
C) True
According to Empirical rule for normal distribution about two-third of data lies within plus or minus one standard deviation from the mean.
D) False
Normal distribution is a continuous probability distribution.
Answer:
TV #3
Step-by-step explanation:
The others cost more.
