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Strike441 [17]
3 years ago
8

I don’t get thiss so can someone help me

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

Step-by-step explanation:

use algabraic expreshens it will help trust me

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How do you know if a function is quadratic??
Anestetic [448]

Answer:

Usually it's in standard form: ax²+bx+c

or vertex form: y=a(x-h)²+k

If you put the graph into a graphing calculator it's going to look like a hill/depression.

Step-by-step explanation:

Standard form ex: 3x²+2x+1

Vertex form ex: y=4(x-1)²-2

7 0
3 years ago
Read 2 more answers
At a small private college 9 / 20 of the students are female if there are 2160 female students how many male students
drek231 [11]

Answer:

4800

Step-by-step explanation:

x is the number of total students

x * 9/20 = number of female students

x * 9/20 = 2160

Multiply each side by 20/9

x * 9/20 * 20/9 = 2160 * 20/9

x =4800

8 0
3 years ago
You purchased an antique guitar for 8600. It is expected to appreciate at 2.4% annually. How long will it take the guitar to dou
eimsori [14]
For it to double its price the price has to be +100% more, and every year you get +2.4%, so you do:
100/2.4≈ 42 years or 41.66666667.. years.
5 0
3 years ago
Marina has $145 to spend. She spends $68. 50 on jeans. T-shirts cost $12. 75. Write and solve an inequality to find the greatest
Kruka [31]

Answer:

6

Step-by-step explanation:

145-68.50 = 76.50

76.20/12.75 = no of t-shirts she can buy

ans= 6

6 0
2 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
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