1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zmey [24]
3 years ago
10

Solve the below question showing work

Mathematics
1 answer:
lutik1710 [3]3 years ago
3 0
<span>There are several ways to find the max of min of a quadratic equation.
Max occurs when t = -b/2a
t = -b/2a = -68/(2*-4.9) = 6.93 second
Max altitude = h(6.93) = 68(6.93)-4.9(6.93^2) = 235.92 meters
</span>
You might be interested in
Please help quick thank you!
ipn [44]

Answer:

Neither

Step-by-step explanation:

After substituting the ordered pair into the equation, none of the pairs satisfy the equation

because 6(3)+3(-2)=12 and 6(2)+3(2)=18.

8 0
3 years ago
Hector's service club is raising money by wrapping presents in the mall. The function f\left(x\right)=3xf(x)=3x describes the am
mestny [16]

Given:

The function f(x) describes the amount of money, in dollars, the club will earn for wrapping x presents.

f(x)=3x

To find:

The f(658).

Solution:

We have,

f(x)=3x

Substitute x=658 to find the value of f(658).

f(658)=3(658)

f(658)=1974

It means, the club will earn $1974 for wrapping 658 presents.

Therefore, f(658)=1974.

7 0
2 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio
olga2289 [7]

Answer:

a) E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

b) E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

Step-by-step explanation:

We assume the following distribution given:

Y       0       1        2        3

P(Y) 0.60 0.25  0.10  0.05

Part a

We can find the expected value with this formula:

E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

Part b

If we want to find the expected value of 100 Y^2 we need to find the expected value of Y^2 and we have:

E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)

And replacing we got:

E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

4 0
3 years ago
What is the answer pls
Anon25 [30]

Answer:

7.375 ib.

Step-by-step explanation:

You just add it all together

3 0
2 years ago
I really need help please
Ahat [919]

Answer:

the first one and the fith one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • Tim's friends gave him 15$ for pizza. If he buys 3 pizzas for 7$ each how much more money does tim need
    15·2 answers
  • Which system of linear inequalities is graphed?
    12·2 answers
  • Roll two dice what are the chances you roll atleast one six
    15·1 answer
  • If the base of a triangle is four times it's height and if the area of the triangle is 242 square millimeters can you find it's
    8·1 answer
  • Km=m/2+p. Solve for m
    13·1 answer
  • Evaluate: 2xy^2-3xy-7 if x=-4and y=5
    7·1 answer
  • I NEED HELP !! Answer to this?
    10·1 answer
  • Tú tienes la mitad de lo que tenías y tendrás el triple de lo que tienes. Si tuvieras lo que tienes, tenías y tendrás, tendrías
    8·1 answer
  • 5
    15·1 answer
  • Which image shows a reflection of the figure below? quick!!!!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!