Answer:
Submarine W. the closest submarine is the one with the lowest depth, -1.5 km (which should actually be written as an absolute value, 1.5km, depth can't be negative).
Answer:
Yes.
Step-by-step explanation:
They are both divisible by 21.
Answer: C 4
Step-by-step explanation:
Use the formula: distance = rate x time
We can say that train 1 travels a distance of x, and train 2 travels a distance of 700 - x
The rate of train 1 is 75 mph, and the rate of train 2 is 100 mph
The time traveled for the two trains will be the same. We can represent that with the variable t.
We have the following equation for train 1:
x = 75t
For train 2, we have this equation:
700 - x = 100t
Use the Substitution Method by replacing x in the equation for train 2 with the value 75t.
700 - 75t = 100t
700 = 175t
700/175 = 4 hours.
It will take 4 hours for the two trains to meet.
Answer: The approximate area of the circle is: <span>3,629.84 cm² .</span>
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Area of a circle, "A" : A = π * r² ;
in which: A = Area of circle ;
π <span>≈ 3.14 ;
</span> r = radius;
radius of a circle, "r" = d / 2 ; in which: "d = diameter" ;
Given "d = 64 cm " ;
r = d / 2 = 64 cm / 2 = 32 cm ;
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So; A = π * r² ;
A ≈ (3.14) * (32 cm)² ;
A ≈ (3.14) * (1156 cm²) ;
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A ≈ 3,629 .84 cm² .
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Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.