Answer:
Hi
Step-by-step explanation:
If it is a system of two unknowns:
1) 4x-8y=5 multiple by 3
2)6x-12y=10 multiple by -2
then
12x-24y=15
-12x+24y=-20
x and y equals 0, so
Answer: no solution
<span>1.
P(</span>at least one of the calculators is defective)=
1- P(none of the selected calculators is defective).
2.
P(none of the selected calculators is defective)
=n(ways of selecting 4 non-defective calculators)/n(total selections of 4)
3.
selecting 4 non-defective calculators can be done in C(35, 4) many ways,
where

while, the total number selections of 4 out of 18+35=53 calculators can be done in C(53, 4) many ways,

4. so, P(none of the selected calculators is defective)=

5. P(at least one of the calculators is defective)=
1- P(none of the selected calculators is defective)=1-0.18=0.82
Answer:0.82
Answer:
hello thank you
Step-by-step explanation: