Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.

1 answer:

6 0

Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

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Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation;

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Alja [10]

Hi!

<h2>Your answer will be: <em>180.</em></h2>

Reason being: <em>183-3=180. Also, 180+3=183.</em>

Hope this helps!

<em>Yours Truly,</em>

<h2><em></em></h2><h2><em>~~~PicklePoppers~~~</em></h2>

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A equation of a linear function in a standard form:

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<h3>Answer: YES. It's a linear function.</h3>

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