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Yuliya22 [10]
3 years ago
12

Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

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three boxes under my stairs contain apples or pears are both each box contains the same number of pieces of fruit the first box
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There are 16 fruits in each of the boxes found under the stairs.

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An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the number of pears, hence:

Number of fruit in first box = 12 + (1/9)x

Number of fruit in second box = number of fruit in third box = (8/9)x ÷ 2 = (4/9)x

Therefore:

12 + (1/9)x = (4/9)x

x = 36

First box = second box = third box = (4/9) * 36 = 16

There are 16 fruits in each of the boxes found under the stairs.

Find out more on equation at: brainly.com/question/2972832

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Can someone please explain the area of a circle in the simplest way possible, no links
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So, for the area of a circle, there should be a line in the middle. Correct?

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