Question

During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16t2 + 56t and h = -16t2 + 156t - 248, where t is the time that has passed since the first ball was hit.
Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

Answer 1

The equations that model both the paths, give the distance or height above the ground with respect to time. So, if we equate both the equations, we can find the time at which the height of two balls is the same.

$-16 t^{2} +56t=-16 t^{2} +156t-248 \\ \\ 248=100t \\ \\ t=2.48$

Therefore, rounding of to nearest tenth, it will take 2.5 seconds after the first ball was hit, for the two balls to be at the same height. 

Answer 2

Answer:

The equations that model both the paths, give the distance or height above the ground with respect to time. So, if we equate both the equations, we can find the time at which the height of two balls is the same.

Therefore, rounding of to nearest tenth, it will take 2.5 seconds after the first ball was hit, for the two balls to be at the same height. 

Step-by-step explanation: