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andre [41]
3 years ago
8

If I gain a rank and go under the points that the rank coust do I lose the rank

Computers and Technology
2 answers:
padilas [110]3 years ago
4 0
This is a good question, and I've wondered about that myself. I'm going to 'report' the question, not because there's anything wrong with it, but to bring it to the attention of the Moderators, so they can tell both of us.
Lana71 [14]3 years ago
4 0
That is a good question that I too once wondered. Based on my experience as a moderator, under normal circumstances, you can't lose your rank.

I can give an example of why that is so. I have the rank of "Ace". To be an Ace, 3,000 points and 15 best answers are required within the past thirty days, once I  gain that rank, I cannot lose that. So this past month, after getting the Ace rank, I got less than 15 best answers, but I did not lose my rank. Likewise, with points, if you get less points than the minimum of your rank, you do not lose your points. Once you gain that rank, its permanent.

There are a few exceptions in which you may possibly lose your rank. But it is not possible if you are a normal, rule following user. The only time I have seen people lose their rank is if they get their account deleted. But do not worry. People only get their account deleted at the most extreme level (such as using profane language and spamming dozens of questions/answers) In which case, they do lose their rank, by deletion.

So based on what I said, do not be afraid. If you follow the rules, even asking dozens of questions that make you fall below the minimum amount to your rank, as long as you have at one point gotten that rank, you cannot lose that rank. I hoped that I answered your question to your preference.

Another note I want to make is that If you have any future questions involving Brainly whatsoever, do not hesitate to ask any of us Moderators. We are here to help.t rank

You might be interested in
Write a program that teaches arithmetic to a young child. The program tests addition and subtraction. In level 1 it tests only a
Natasha2012 [34]

Answer:

import random

class Arithmetics(object):

   trial = 2

   score = 0

   is_end = "Y"

   

   def start(self):

       while self. is_end == "Y":

           self. level1()

           self. level2()

           self. level3()

           self. is_end = input("Do you want to play again? Y/N: "). upper()

       quit()

   def level1(self):

       print("--------------------Level 1--------------------\n\n Addition:")

       for _ in iter(list, 0):

           num1 = random.randint(1,5)

           num2 = random.randint(1,5)

           if self. score == 5:

               print("Congrat! advance to next level\n")

               self. init_()

               break

           print(f"{num1} + {num2}")

           result = int(input("Your answer: "))

           if result == num1 + num2:

               self. increase_score()

           elif self. trial == 0:

               print("Sorry dear, you failed to pass the text.")

               self. end_game()

           else:

               self. trial_reduce()

   def level2(self):

       print("--------------------Level 2--------------------\n\n Addition again:")

       for _ in iter(list, 0):

           num1 = random. randint(1,9)

           num2 = random. randint(1,9)

           if self. score == 5:

               print("Congrat! advance to next level\n")

               self. init_()

               break

           print(f"{num1} + {num2}")

           result = int(input("Your answer: "))

           if result == num1 + num2:

               self. increase_score()

           elif self. trial == 0:

               print("Sorry dear, you failed to pass the text.")

               self. end_game()

           else:

               self. trial_reduce()

   def level3(self):

           print("--------------------Level 3--------------------\n\n Subtraction:")

           for _ in iter(list, 0):

               denum = random. randint(6,9)

               num = random. randint(1,5)

               if self. score == 5:

                   self. init_()

                   self. end_game()

                   break

               print(f"{denum} - {num}")

               result = int(input("Your answer: "))

               if result == denum - num:

                   self. increase_score()

               elif self. trial == 0:

                   print("Sorry dear, you failed to pass the text.")

                   self. end_game()

               else:

                   self. trial_reduce()

   #classmethod

   def trial_reduce(cls):

       cls. trial -= 1

   #classmethod

   def increase_score(cls):

       cls. score += 1

   #classmethod

   def init_(cls):

       cls. trial = 2

       cls. score = 0

   def end_game(self):

       print("Congrats kiddo! You are a math wiz.")

game = Arithmetics()

game. start()

Explanation:

The python class defines the arithmetics class with three-level mathematics for children defined as methods for the class. There are three class methods namely; 'trial_reduce', 'increase_score', and 'init_' with each of them decreasing the trial attribute, increasing the score attribute by one, and initializing the class attributes to its initial state.

The 'end_game' prints a message at the end of the program. Each level is in a loop and counts five times if the answers are correct.

7 0
3 years ago
Which of the following is the MOST important consideration when planning your budget?
Sladkaya [172]
C.budget for fixed expenses before flexiable expenses 

3 0
3 years ago
Read 2 more answers
In C++ :
elena-s [515]

Answer::

//Program is written in C++ Programming Language

// Comments are used for explanatory purpose

#include

#include

#include

#include

using namespace std;

int main(){

ifstream file; // File stream object

string name; // To hold the file name

string inputLine; // To hold a line of input

int lines = 0; // Line counter

int lineNum = 1; // Line number to display

// Get the file name.

cout << "Enter the file name: ";

getline(cin, name);// Open the file.

file.open(name.c_str());// Test for errors.

if (!file){

// There was an error so display an error

// message and end the PROGRAM.

cout << "Error opening " << name << endl;

exit(EXIT_FAILURE);

}

// Read the contents of the file and display

// each line with a line number.

// Get a line from the file.

getline(file, inputLine, '\n');

while (!file.fail()){

// Display the line.

cout << setw(3) << right << lineNum<< ":" << inputLine << endl;

// Update the line DISPLAY COUNTER for the next line.

lineNum++;// Update the total line counter.

lines++;// If we've displayed the 24th line, pause the screen.

if (lines == 24){

cout << "Press ENTER to CONTINUE...";

cin.get();

lines = 0;

}

// Get a line from the file.

getline(file, inputLine, '\n');}

//Close the file.

file.close();

return 0;}

8 0
4 years ago
Consider the efficiency of locating the kth element in a singly-linked list. How does that compare to locating the kth element i
eimsori [14]

Answer:

Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list

Explanation:

Assuming that  both lists have firs_t and last_ pointers.

For a singly-linked list ; when locating a kth element, you have iterate through a number of k-1 elements which means that locating an element will be done only in one ( 1 ) direction

For a Doubly-linked list : To locate the Kth element can be done from two ( directions ) i.e. if the Kth element can found either by traversing the number of elements before it or after it . This makes finding the Kth element faster because the shortest route can be taken.

<em>Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list </em>

4 0
3 years ago
Help me help you...........
lyudmila [28]

Answer:

the 4th answer

Explanation:

w stage for width, h for height.

6 0
2 years ago
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