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nexus9112 [7]
3 years ago
14

Richard owns a chain of hardware stores. He wants to update the store website and write a numbered list of all the items in his

store. Which tag will he use for this purpose? A. B. C. D. E.

Computers and Technology
2 answers:
Digiron [165]3 years ago
8 0
Use ordered list
  1. tag and put each item inside of a list item
  2. tag.
docker41 [41]3 years ago
5 0

Answer:

Use <ol> and <li> tags

Explanation:

<!-- ordered list tag i.e. '<ol>'   -->

<ol>

 <!-- list item tag i.e. '<li>'  -->

            <li> A </li>

            <li> B </li>

            <li> C </li>

            <li> D </li>

            <li> E </li>

       </ol>

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Using the scenario below, answer the following questions:
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Answer:

Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

         boolean flag=false;

         int total_mile=0;

         double avg_mile;

       // part 1, create and initialize array

       int inp[]={2,5,9,11,13,17,20,22,24,26};

       

       System.out.print("miles ran per week: ");

       // print the miles per week of train

       for(int x=0;x<10;x++)

       {

       System.out.print(inp[x]+" ");

       }

        System.out.println();

       //part 2, print the value of index 2 in the list

       System.out.println("value at index 2: "+inp[2]+" miles");

       //part 3, find length of array

       System.out.println("list length: "+inp.length);

     

       // part 4, calculate total mile and average

       for(int y=0;y<10;y++)

       {

       total_mile=total_mile+inp[y];

       }

       System.out.println("total miles ran: "+total_mile+" miles");

       

       avg_mile=total_mile/10.0;

       System.out.println("average no of miles ran= "+avg_mile+" miles");

       

     // part 5, check 4 exist in the list or not

       for(int k=0;k<10;k++)

       {

       if(inp[k]==4)

       {

       flag=true;

       break;

           }

       }

           if(flag)

           System.out.println("4 exist in the list.");

           else

            System.out.println("4 doesn't exists in the list.");  

       

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create and initialize array with list value equals to 2 and maximum value 26. Print the miles of each week.Then find the value of miles at index 2 in the list.Next find the length of the array and print it.Calculate total miles ran of 10 weeks.Then calculate the average miles by dividing the total with 10. In the array, check 4 exist or not.

Output:

miles ran per week: 2 5 9 11 13 17 20 22 24 26                                                                            

value at index 2: 9 miles                                                                                                  

list length: 10                                                                                                            

total miles ran: 149 miles                                                                                                

average no of miles ran= 14.9 miles                                                                                        

4 doesn't exists

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