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3 years ago

Can someone tell me the answer?

Mathematics

1 answer:

Soloha48 [4]3 years ago

4 0

Answer:

Ashley p ≈ 10 d

Carly p ≈ 11 d ± 40

Step-by-step explanation:

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PLEASE HELP!!!! ASAP!!!!!

SCORPION-xisa [38]

-6 5 -3 is the corrdante did those sir

8 0

2 years ago

How do u make 25 m to *what* cm?

vodka [1.7K]

Answer:

2500 cm

Step-by-step explanation:

1 meter = 100 cm

25m x 100 = 2500 cm

7 0

2 years ago

Read 2 more answers

PLEASE HELP!!!!

Ilya [14]

Answer:

dang

Step-by-step explanation:

A. x – 58 = 129 yes

B. x + 58 = 129 no

C. 180 – 129 − 59 = x yes

D. 129 – 58 = xyes

E. (180 – 129) – 51 + x = 180no

hope this helps

7 0

2 years ago

Read 2 more answers

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$

Another identity:

$\displaystyle \large{\sin^2x+\cos^2x=1}$

Therefore:

$\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}$

Hence proved, this is proof by using identity helping to find the specific identity.

6 0

2 years ago

Last month,James bought a tree that grows 3 cm each day. It was 5 cm tall when he bought it and now it is 68 cm tall. The equati

pshichka [43]

Answer:

james has had the plant 21 days

Step-by-step explanation:

5 +3d= 68

5+3d-5= 68-5

3d= 63

3d/3=63/3

d=21

4 0

3 years ago