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Vika [28.1K]
3 years ago
14

Pam read 126 pages of her summer reading book in 3 hours. Zack read 180 pages of his summer reading book in 4 hours. If they con

tinue to read at the same speeds, will they both finish the 215 page book after 5 total hours of reading?
Mathematics
2 answers:
LiRa [457]3 years ago
8 0
Zack reads faster so he will finish first
Pam= 126/3 = 42/1
Zack= 180/4 =45/1
Now multiply the unit rates by 5 each
Pam= 210/5
Zack= 225/5
IrinaVladis [17]3 years ago
4 0

Answer:

Zack can finish the 215 page book after 5 total hours of reading but Pam cannot.

Step-by-step explanation:

Pam read 126 pages of her summer reading book in 3 hours.

\texttt{Speed of Pam =}\frac{126}{3}=42page/hour

Zack read 180 pages of his summer reading book in 4 hours. \texttt{Speed of Zack =}\frac{180}{4}=45page/hour

Number of pages Pam read in 5 hours = 5 x 42 = 210 pages

Number of pages Zack read in 5 hours = 5 x 45 = 225 pages

We need to find will they both finish the 215 page book after 5 total hours of reading,

Here number of pages read by Zack is greater than 215 and number of pages read by Pam is less than 215.

So Zack can finish the 215 page book after 5 total hours of reading but Pam cannot.

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4 years ago
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

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x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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