Pam read 126 pages of her summer reading book in 3 hours. Zack read 180 pages of his summer reading book in 4 hours. If they con
2 answers:
Answer:
Zack can finish the 215 page book after 5 total hours of reading but Pam cannot.
Step-by-step explanation:
Pam read 126 pages of her summer reading book in 3 hours.
Zack read 180 pages of his summer reading book in 4 hours.
Number of pages Pam read in 5 hours = 5 x 42 = 210 pages
Number of pages Zack read in 5 hours = 5 x 45 = 225 pages
We need to find will they both finish the 215 page book after 5 total hours of reading,
Here number of pages read by Zack is greater than 215 and number of pages read by Pam is less than 215.
So Zack can finish the 215 page book after 5 total hours of reading but Pam cannot.
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The correct question statement is:
A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in
. Find 
.
Solution:
Part 1:
means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.
So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:
Thus the set compliment of E will contain the elements {4,5,6}.So
= {4,5,6}
Part 2)
means probability that if we select any number from the Sample Space S, it will belong the set E compliment.
= (Number of Elements in 
)/Number of elements in S
Number of elements in set S = n(S) = 12
Number of elements in set = 
=3
So,
A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in
Solution:
Part 1:
So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:
Thus the set compliment of E will contain the elements {4,5,6}.So
Part 2)
Number of elements in set S = n(S) = 12
Number of elements in set
So,