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vlada-n [284]
3 years ago
6

Graph and label Point H at 1.5 , negative 6 thirds

Mathematics
1 answer:
andre [41]3 years ago
7 0
They are actually asking for 1.5 and -2 so the answer will be coordinated at approximately half past 1 and on -2 which is located on the right lower quadrant
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Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the
kvasek [131]
The axis of symmetry of a quadratic function f(x)=ax^2+bx+c is given by the equation x=h, where h is the x-coordinate of the vertex and is equal to \frac{-b}{2a}.

1.
f(x)=4x^2-1 \\
a=4 \\ b=0 \\ \Downarrow \\
h=\frac{-0}{2 \times 4}=0 \\ \\
\hbox{the axis of symmetry:} \\
x=0

2.
g(x)=x^2-8x+5 \\
a=1 \\ b=-8 \\ \Downarrow \\ h=\frac{-(-8)}{2 \times 1}=\frac{8}{2}=4 \\ \\
\hbox{the axis of symmetry:} \\
x=4

3.
h(x)=-3x^2-12x+1 \\
a=-3 \\ b=-12 \\ \Downarrow \\ h=\frac{-(-12)}{2 \times (-3)}=\frac{12}{-6}=-2 \\ \\
\hbox{the axis of symmetry: \\
x=-2

The functions ranked from least to greatest based on their axis of symmetry: h(x), f(x), g(x).
7 0
2 years ago
The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.
Pie

Answer:

9.3 hours

Step-by-step explanation:

Given

y = 2.89\sin(0.0145x-1.40) + 10.99.

Required

Hours of sunlight on Feb 21, 2013

First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013

days = 52

So:

x = 52

So, we have:

y = 2.89\sin(0.0145x-1.40) + 10.99.

y = 2.89\sin(0.0145*52-1.40) + 10.99.

y = 2.89\sin(0.754-1.40) + 10.99.

y = 2.89\sin(-0.646) + 10.99.

y = 2.89*-0.6020 + 10.99.

y = -1.740 + 10.99.

y = 9.25

<em></em>y = 9.3<em> --- approximated</em>

8 0
2 years ago
Marina is currently 14 years older than her cousin joey. in 5 years she will be 3 times as old as joey. if you let x represent j
serious [3.7K]
The expression is 14x
4 0
3 years ago
What does the A equal to in a + (-7) = 3
Korolek [52]
A = 10

Step by step

3+7=10
10+(-7)=3
7 0
2 years ago
Write (75d)1/2 in radical form
Kitty [74]
(75d)^{ \frac{1}{2} }= \sqrt{75d}=5 \sqrt{3d}
7 0
3 years ago
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