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posledela
3 years ago
7

if, while training for a marathon, you run 88 miles in 2 4/5 months, how many miles did you run each month?

Mathematics
1 answer:
nlexa [21]3 years ago
8 0
Hi,

Let's solve this problem mathematically.

2\frac{4}{5} = 2.8
88 \div 2.8 = 31.42

Result = 31.42
Hope this helps!
r3t40
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a purse contains 25p coins and 50 p coins. the total amount in the purse is rs.25. if the number of 50 p coins is double the num
erica [24]
Let the total no. of 25 p coins be x
50p coins = 2x 

Value of 25 p coins ( in rupees) = 0.25*x =0.25x
Value of 50p coins ( in rupees) = 0.5*2x = x

0.25x+x = 25
1.25x =25
x = 25/1.25 = 20

no. if 25p coins = 20
and 50p coins = 2*20 = 40

4 0
3 years ago
0.5 recurring as a fraction​
Klio2033 [76]

0.5 = 5/10 = 1/2

The answer is 1/2

5 0
2 years ago
Read 2 more answers
Suppose that 45% of people have dogs. If two people are randomly chosen, what is the probability that they both have a dog
mylen [45]

Answer:

P(Dogs) = 0.2025

Step-by-step explanation:

Given

Proportion, p = 45\%

Required

Probability of two people having dog

First, we have to convert the given parameter to decimal

p = \frac{45}{100}

p = 0.45

Let P(Dogs) represent the required probability;

This is calculated as thus;

<em>P(Dogs) = Probability of first person having a dog * Probability of second person having a dog</em>

<em />

P(Dogs) = p * p

P(Dogs) = 0.45 * 0.45

P(Dogs) = 0.45^2

P(Dogs) = 0.2025

<em>Hence, the probability of 2 people having a dog is </em>P(Dogs) = 0.2025<em />

4 0
3 years ago
Can someone please help with this trig question?
atroni [7]
First we must understand how to write a logarithmic function:

log_{b}a=x

In the equation above, b is the base, x is the exponent, and a is the answer. These same variables can be rearranged to be expressed as an exponential equation as followed:

b^x=a

Next, we need to understand basic logarithm rules.

1. When a value is raised to a power, we can move the exponent to the front of the logarithm. Example:

log(a^2) = 2log(a)

2. When two variables are multiplied together, we can add the logarithms of the individual variables together. Example:

log(ab) = log(a) + log(b)

3. When a variable is divided by another variable, we can subtract the logarithms of the individual variables. Example:

log(a/b) = log(a) - log(b)

Now we can use these rules to solve the problem.

log(r)=log( \sqrt[3]{ \frac{A^2B}{C} } )

We can rewrite the cube root as:

log(r) = log( (\frac{A^2B}{C})^ \frac{1}{3} )

Now we can move  the one-third to the front:

log(r) =  \frac{1}{3} log( \frac{A^2B}{C} )

Now we can split up the logarithm:

log(r) =  \frac{1}{3} (log(A^2)+log(B)-log(C))

Finally, we can move the exponent to the front of the log of A:

log(r) = \frac{1}{3} (2log(A)+log(B)-log(C))

Distribute the one-third to get the answer:

log(r) = \frac{2}{3} log(A) +  \frac{1}{3} log(B) -  \frac{1}{3} log(C)

The answer is (4).


3 0
3 years ago
Only the smartest person in their math class can help me with this difficult problem!!!
vodomira [7]

Step-by-step explanation:

\tt{(5 {x}^{3}  - 3x + 6) - (2 {x}^{2}  - 4x + 8)}

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ \tt{5 {x}^{3}  - 3x + 6 - 2 {x}^{2}  + 4x - 8}

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶ \tt{5 {x}^{3}  - 3x + 4x + 6 - 8 - 2 {x}}^{2}

⟶ \tt{5 {x}^{3}  + x - 2 - 2 {x}^{2} }

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

\red{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \tt{5 {x}^{3}  - 2 {x}^{2}  + x - 2}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
2 years ago
Read 2 more answers
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