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maw [93]
3 years ago
13

What is the answer ?

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer:

exponential

Step-by-step explanation:

exponential functions will always have a horizontal asymptote

Serhud [2]3 years ago
7 0
The answer is a)exponential
You might be interested in
Please help me if u can that would be GREAT Thanks
kirill115 [55]

Answer:

12.5 or 25/2!

Step-by-step explanation:

Multiply the first two as improper fractions then divide it by 2/3!

5 0
3 years ago
You paid $44 to a loan company for the use of $1,153 for 119 days, what annual rate of interest did they charge? (Assume a 360-d
Zigmanuir [339]

Answer:

Ans. A) The annual rate that the company charged was 11.996%; B) if they charged you 11.186% annual rate, you would have to pay $41.14

Step-by-step explanation:

Hi, first we have to find out what is the effective 119 days rate and then turn it into an annual rate. This is as follows.

r(Effective119Days)=\frac{44}{1,153} x100=0.038161

So the charged rate was 3.816% effective, 119 days, now let´s make it an annual rate.

r(annual)=(1+0.038161)^{\frac{360}{119} } -1=0.119965

This means that the equivalent rate to 3.816% effective 119 days ys 11.996% effective annually (or just annual).

Now, if they were to charge you 11.186% annual, you would have to make this rate effective 119 days, and then, multiply it by the principal ($1,153). Let´s change the rate first.

r(Effective119Days)=(1+0.11186)^{\frac{119}{360} -1}=0.03568

And the money that you will have to pay in interest is $1,153*0.03568=$41.14

Best of luck

7 0
3 years ago
Find the rectangular coordinates of the point with the polar coordinates ordered pair 7 comma 2 pi divided by 3.
Morgarella [4.7K]

Answer:

\left(-\dfrac{7}{2},\dfrac{7\sqrt{3}}{2}\right).

Step-by-step explanation:

The given point is

\left(7,\dfrac{2\pi}{3}\right)

We need to find the rectangular coordinates of the given point.

If a polar coordinate is (r,\theta), then  

x=r\cos theta

y=r\sin theta

In the given point \left(7,\dfrac{2\pi}{3}\right),

r=7,\theta=\dfrac{2\pi}{3}

Now,

x=7\cos \dfrac{2\pi}{3}

x=7\cos \left(\pi-\dfrac{\pi}{3}\right)

x=-7\cos \left(\dfrac{\pi}{3}\right)

x=-7\left(\dfrac{1}{2}\right)

x=-\dfrac{7}{2}

and,

y=7\sin \dfrac{2\pi}{3}

y=7\sin \left(\pi-\dfrac{\pi}{3}\right)

y=7\sin \left(\dfrac{\pi}{3}\right)

y=7\left(\dfrac{\sqrt{3}}{2}\right)

y=\dfrac{7\sqrt{3}}{2}

Therefore, the required point is \left(-\dfrac{7}{2},\dfrac{7\sqrt{3}}{2}\right).

3 0
3 years ago
A circular wall clock has a diameter of 18 cm which measurement is closest to the circumstances of the clock in cm
BabaBlast [244]

Answer:

56.55cm

Step-by-step explanation:

I assume that you mean circumference instead of circumstances, so if so then that is the answer

3 0
3 years ago
See attached photo, calc ab, please show work too!
SSSSS [86.1K]

Answer:

(B) 15

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Rule [Chain Rule]: \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = f(g(x))

h'(1) = ?

<u>Step 2: Differentiate</u>

  1. Chain Rule:                                                                                                        h'(x) = f'(g(x)) · g'(x)

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              h'(1) = f'(g(1)) · g'(1)
  2. [Values] Substitute in function values:                                                            h'(1) = f'(3) · -3
  3. [Values] Substitute in derivative function values:                                          h'(1) = -5 · -3
  4. Multiply:                                                                                                             h'(1) = 15

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0
3 years ago
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