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ivanzaharov [21]

3 years ago

10

Find a quadratic function with the given x-values as the only two REAL zeros. x=-2 and x=8. Please show work! Will mark Brainlie

st!

1 answer:

posledela3 years ago

3 0

f(x) = (x- zero) * (x -zero)

f(x) = (x--2) (x-8)

f(x) = (x+2) (x-8)

if you need it multiplied out

f(x) = x^2 +2x -8x-16

f(x) = x^2 -6x-16

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(x ÷ 8) + 23 – 4 = 36

kifflom [539]

Answer:

(x ÷ 8) + 23 – 4 = 36

x = 136

Step-by-step explanation:

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2 years ago

The product of two

inessss [21]

Answer:

11 and 12

Step-by-step explanation:

x(x+1)=132

x^2+x=132

x^2+x-132=0

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x = 11 or x = -12

when x=11 ,

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7 0

4 years ago

57times71= please tell me the answer

Phoenix [80]

57 times 71 = 4047 Hope that helps!

5 0

3 years ago

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What is the solution to the system of equations below? y= -4/5 x + and y = –30

Naya [18.7K]

Answer:

$x=37.5$

Step-by-step explanation:

We need to find the solution to the following system of equations:

$y = -\frac{4}{5} x$ and $y=-30$

By plugging the value of 'y' into the first equation we have that:

$-30 = -\frac{4}{5} x$ ⇒ $30=\frac{4}{5} x$

Solving for 'x' we have:

$x=37.5$

So, the solution to the system of equation is: (37.5, -30)

8 0

3 years ago

Suppose that rectangle ABCD is dilated to A'B'C'D' by a scale factor of 3.5 with a center of dilation at the origin. What is the

posledela

The answer to that question Would be C, because I have already taken this unit test prep assignment.

3 0

3 years ago

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