Question

What is the point slope equation of the line with slope -12 that goes through the points (5, 3)?

Answer 1

The point-slope form of ay line is:

y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line.

In this case we are given that m=-12 and (x1,y1) is (5,3) so

y-3=-12(x-5)

Answer 2

Answer:

y = -12x + 63

Step-by-step explanation:

- The equation of a line in a cartesian coordinate system is given by the following linear relationship:

                                    y = mx + c

- The constants m and c are to be determined.

- The constant m denotes the slope of the line which is given as -12.

- To evaluate constant c we will plug the slope m = -12 and use the given point ( 5 , 3 ) as the lines passes through it. Hence, we have:

                                  y = -12x + c

                                  3 = -12(5) + c

                                  3 = - 60 + c

                                  c = 63

- Then the equation of the line can be expressed by plugging in the constants m and c as follows:

                                 y = -12x + 63