At the end of the year, you pay 320 dollars.Just multiply 15 by 12, and add the sum to 140. Hope this helps!
Answer:
The probability that components #1 and #2 fail, and at least one of components #3 and #4 fails is 0.031875
Step-by-step explanation:
Let's define the following events,
F1: Component #1 fails
F2: Component #2 fails
F3: Component #3 fails
F4: Component #4 fails
We are looking for the following probability
P[(F1∩F2)∩(F3∪F4)]
using distributive laws we have
P[(F1∩F2)∩(F3∪F4)] = P[(F1∩F2∩F3)∪(F1∩F2∩F4)] = P(F1∩F2∩F3) + P(F1∩F2∩F4) - P(F1∩F2∩F3∩F4) = P(F1)P(F2)P(F3) + P(F1)P(F2)P(F4) - P(F1)P(F2)P(F3)P(F4) = (0.25)(0.25)(0.3) + (0.25)(0.25)(0.3) - (0.25)(0.25)(0.3)(0.3)=0.031875
by the assumption of independence (the components fail independently) and because P(F1) = P(F2) = 0.25, P(F3) = P(F4) = 0.3
There is no question and and therefore cannot be answered
Answer: mean is 66 and the median height is 68.
Step-by-step explanation: uh I dont know what to put here....?
Answer:
B(2,10)
D'(4,-1)
Step-by-step explanation:
ok to find this we need to know what the translation is
from (2,2) to (-4,-1)
subtract 6 from x and subtract 3 from y
im gonna chak another just in case
3rd one
(10,10) to (4,7)
same rule
so for the second one they give us (-4,7)
to get this we subtracted 6 from x and 3 from y from original so
lets work backwards
add 6 from x and add 3 from y
(-4,7)+(6,3)
answer(2,10)
now D'
subtract 6 from x and 3 from y
(10,2)-(6,3)
(4,-1)