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n200080 [17]
2 years ago
10

Two numbers are in a ratio 11:7. If the smaller number is 700, what is the larger number? Pls tell with steps

Mathematics
2 answers:
Nutka1998 [239]2 years ago
6 0

Answer:

The larger number is 1100

Step-by-step explanation:

Let larger number be x

We have

\frac{x}{700} =\frac{11}{7} \\\\x=100\times11\\\\=1100

andre [41]2 years ago
4 0

Answer:

The larger number is <u>1100</u><u>.</u>

Step-by-step explanation:

<u>Solution</u> :

Let the,

  • >> Larger number be <em>11x</em><em>.</em>
  • >> Smaller number be <em>7x</em><em>.</em>

Now, According to the question :

\begin{gathered} \dashrightarrow\sf{Smaller \:  number} =  \tt{700} \end{gathered}

\begin{gathered} \dashrightarrow\sf{7x}= \tt{700} \end{gathered}

\begin{gathered} \dashrightarrow\sf{x}= \tt{700 \div 7} \end{gathered}

\begin{gathered} \dashrightarrow\sf{x}= \tt{ \dfrac{700}{7} } \end{gathered}

\begin{gathered} \dashrightarrow\sf{x}= \tt{\cancel{\dfrac{700}{7}}} \end{gathered}

\begin{gathered} \dashrightarrow  \sf{x}= \tt{100} \end{gathered}

Hence, the value of x is 100.

Now, calculating the larger number :

\begin{gathered} \dashrightarrow\sf{Larger \:  number} =  \tt{11x} \end{gathered}

\begin{gathered} \dashrightarrow\sf{Larger \:  number} =  \tt{11 \times 100} \end{gathered}

\begin{gathered} \dashrightarrow\sf{Larger \:  number} =  \tt{1100} \end{gathered}

Hence, the larger number is 1100

\rule{300}{1.5}

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Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

The answers are confirmed.

7 0
2 years ago
I WILL MARK YOU BRAINLIEST PLS HELP!!! The image below shows two dilated figures with lines AB and A’B’ drawn. If the larger fig
geniusboy [140]

Answer:

Lines AB and A'B' are similar, line A'B' being three times the size of line AB. They would not be congruent since a dilation isn't a rigid transformation but they would be similar. Their lengths would also be expressed in the form of a ratio which would be 1:3 if you do AB to A'B' and 3:1 if you do A'B' to AB. Hope this helped! :)

Step-by-step explanation:

The relationship between two lines AB and A’B’ is A'B'=3AB.

It is given that in the given figure larger figure was dilated using a scale factor of 3. It means the smaller and larger figures are similar and there corresponding sides are in the ratio 1:3.

The line AB connecting the two points of the smaller figure and line A'B' connecting the two points of the larger figure.

Since A'B' is corresponding line segment of AB in larger figure, therefore the ratio of AB to A'B' is 1:3.

By cross multiplication we get

The length of segment A'B' is 3 times of AB.

MARK ME BRAINLIEST!

6 0
3 years ago
A circle has radius 50 cm. Which number would be close to the area
ale4655 [162]

Answer:

look do is gone eat

Step-by-step explanation:

ok

7 0
3 years ago
Need help with this asap please
Rainbow [258]
Since they are similar, that means they are proportionally the same.
So KL is similar to PN
JL is similar to PM

So,
You need to find how much bigger is the second triangle from first.
It is proportionally scaled up.

KL/JL = PN/ PM

You basically put in order of triangles. Left triangle on left side of equal sign and right triangle on right side of equal sign. You put in denominator the similar sides and numerator the similar sides (the side that is similar to the side of the other triangle)

5/6 = PN / 9
Cross-multiply
PN * 6 = 5*9
6PN = 45
PN =45/6

PN =7.5
5 0
2 years ago
I need help with this question. It's about inequalities. ​
PtichkaEL [24]
N is greater than it equal to 3

So you put a shaded in for a three and draw a line to the right


I think :)
5 0
3 years ago
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