The answer is 7. If you follow the order of PEMDAS this is an easy question.
Answer:
he sum of the measures of two complementary angles is 90 degrees
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
In this problem we have that
m∠ABD and m∠DBC are complementary
so
m∠ABD + m∠DBC=90° -----> by complementary angles
and
(m∠ABD + m∠DBC)+m∠EBC=180° -----> by a linear pair
Find the measure of angle EBC
substitute the given values
(90°)+m∠EBC=180°
∠EBC=180°-90°=90°
Answer:
3√3
Step-by-step explanation:
For the problem shown here, your answer 3√3 is correct.
When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:
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If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.
<u>Example</u>:
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It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.
9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.
Please discuss this question with your teacher.
Answer:
6
Step-by-step explanation:
Solve x then y after..
Hello there! Given that normal dice are numbered 1-6, individually rolling a 4 or a 5 would give a 1/6 probability. That converts to about 17% as a percentage because we can multiply 1 by 100 to get 100/6, then divide 100 by 6 to get 16.6666. When rounding, that gives approximately 17%. However, if we combined probabilities, we would find that rolling a 4 or a 5 collectively gives a 2/6 probability, which is approximately 33% as a decimal.
In terms of individual probabilities, you would be 17% likely to roll one of them. In terms of collectiveness, the likelihood of rolling a 4 or 5 would render 33% on each die. If you need additional help, let me know and I will gladly assist you.
