<span>Your answer is -0.5 hope it helps:)
Also, I changed my pfp so know it's not team 10 no more</span>
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
Answer:
(-1,2)
Step-by-step explanation:
y = -2x ______(1)
7x - 8y = -23 ________(2)
Substituting the value of y in eqn.(1) into eqn (2);
7x - 8(-2x) = -23
7x + 16x = -23
23x = -23
x = -1
y = -2(-1) = 2.
The slope is 2
Hopes this helps in any sort of way
