Answer:
0
Step-by-step explanation:
It may say combine, but it`s subtraction soooo it`s 0.
The Midpoint 1 = (1,1), Mid point 2 = (3,3 ) and slope is 1 of the given points of the line.
<h3>What is the slope of line?</h3>
The slope of a line segment is a measure of the steepness of the line segment. It is the ratio of rise (the change in vertical height between the endpoints) over run (the change in horizontal length between the endpoints.
The slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).
Whenever the equation of a line is written in the form y = mx + b, it is called the slope-intercept form of the equation. The m is the slope of the line.
Midpoints of 1 line segment are -
= (2+0 / 2 , 4-2 / 2)
= (1,1)
Mid points of line 2 =
= (5+1 / 2, 1+5 / 2)
= (3,3)
slope -
The required slope = rise / run
= (y1-y2)/(x1-x2)
= (1-3)/(1-3)
= 1
Therefore, the Midpoint 1 = (1,1), Mid point 2 = (3,3 ) and slope is 1 of the given points of the line.
To learn more about slope and mind-points from the given link
brainly.com/question/5792883
#SPJ4
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
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