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salantis [7]
3 years ago
13

Nine lollies cost less than $10, while ten lollies cost more than $11 how much does each lollipop cost?

Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

$1.10

Step-by-step explanation:

1.10 times 10

irina [24]3 years ago
5 0

$21 it will cost for lollipop

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Which expressions are equivalent to 4b ?
aivan3 [116]

Answer:

They are b and c.

Step-by-step explanation:

Let's simplify each expression:

a. b+2 (b+2b)

= b + 2b + 4b = 7b.

b.  3b + b = 4b.

c. 2(2b) = 2 * 2b = 4b.

5 0
3 years ago
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Solve system of equation 4b-2d=5, -2b+d=1
Fed [463]

Answer:

no solution

Step-by-step explanation:

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3 years ago
How do I Factor -12 out of -24k + 120
Juli2301 [7.4K]

Answer:

-12(2k-10)

Step-by-step explanation:

You divide each term by -12, and then put -12 outside of the parenthesis. The parenthesis contain the new equation you just created.

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2 years ago
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1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

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