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Sergeeva-Olga [200]
4 years ago
8

Help i dont get this question!

Mathematics
1 answer:
Gennadij [26K]4 years ago
7 0
Because the perimeter is all the sides added:

P = side + side + side
4x + 3y = x + y + x + y + s
2x + y = s

Hope this helps!
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You have that \int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2.

To compute I_1 you set y=x^2+2x+2, so dy=2x+2\; dx. Therefore, I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2).

For I_2 observe that x^2+2x+2=(x+1)^2+1. Let y=x+1. Then dy=dx and I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1).

So, \int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c.
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Lapatulllka [165]

Answer:

(x-1)!

Step-by-step explanation:

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