Answer:
Step-by-step explanation:
you just do, everyone in here needs help so i dont think theres people in here just messing arround, you can trust.
Let
x--------> the border’s length
y--------> the border’s width
P--------> perimeter of the border
we know that
x=5+y------> equation 1
P=2*[x+y]-----> P=2x+2y
P <=180 ft
(2x+2y) <= 180-------> equation 2
substitute the equation 1 in equation 2
2*[5+y]+2y <= 180
10+2y+2y <= 180
4y <= 180-10
4y <=170
y <=42.5 ft
so
the maximum value of the width is 42.5 ft
for y=42.5 ft
x=42.5+5------> x=47.5 ft
the answer is
the width of the border is less than or equal to 42.5 ft
Y=3x-5
Y=5/4x+3/4
The solution to the equations is in the picture
Answer:
2sinθ + cosθ = 2
Step-by-step explanation:
12 cos θ - 16 sinθ = 0
=> 3 cos θ -4 sin θ = 0
=> tanθ = 3/4
let P = 3x
B = 4x
=> H= 5x
=> sinθ = P/H = 3/5
cosθ = B/H = 4/5
2sinθ + cosθ
= 2× 3/5 + 4/5
= 6/5+4/5
= 10/5
= 2
=> 2sinθ + cosθ = 2
Answer:
14 m
Step-by-step explanation:
For the triangle, you use the formula A=1/2bh. So in this case it's 3×4×1/2. 3×4 is 12, times 1/2 is 6 m. Now for the rectangle it's just 2×4 which is 8. 8+6 is 14. Hope this helps! If you are still confused please comment!
