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Nataly_w [17]
2 years ago
7

Can anyone solve it.??​

Mathematics
2 answers:
bulgar [2K]2 years ago
3 0
The answer will be f √7 / 3 + 5 √7 / 14.
Kruka [31]2 years ago
3 0

\dfrac{\sqrt7}{3}+\dfrac{5}{2\sqrt7}=\dfrac{\sqrt7}{3}+\dfrac{5\sqrt7}{14}=\dfrac{14\sqrt7}{42}+\dfrac{15\sqrt7}{42}=\dfrac{29\sqrt7}{42}

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An open box with a square base is to be constructed from 84 square inches of material. The height of the box is 2 inches. What a
riadik2000 [5.3K]
Your surface area is: S=x^2+4xh=84 square inches and h=2 inches; so you get:
x^2+(4×2)x=84
x^2+8x-84=0 qhich is a quadratic equation. Using the quadratic formula you get two results for x:
x1=-14 and x2=6
choose the second (positive)
6 0
4 years ago
Given the data set below, find the mean,
Virty [35]
Answer: A) 10
4+8+21+9+12+6=60
60/6= 10
To find the mean, you’ll add all the numbers and then divided be however many there are.
8 0
3 years ago
Please help me out with these questions. It's trigonometry
sergij07 [2.7K]

Step-by-step explanation:

<em>LOOK AT THE PICTURE</em>

In ΔABC:

\sin\alpha=\dfrac{x}{y+p}\\\\\cos\alpha=\dfrac{q}{y+p}\\\\\tan\alpha=\dfrac{x}{q}

In ΔADC

\sin\alpha=\dfrac{y}{x}\\\\\cos\alpha=\dfrac{z}{x}\\\\\tan\alpha=\dfrac{y}{z}

In ΔBCD

\sin\alpha=\dfrac{z}{q}\\\\\cos\alpha=\dfrac{p}{q}\\\\\tan\alpha=\dfrac{z}{p}

5 0
3 years ago
1/3x-4=3/4x+1. 12(1/3x)-4=12(3/4x) + 1. 4x -4=9x + 1. -5=5x. X = -1<br><br> Solve
jek_recluse [69]

Answer:

x=-12

Step-by-step explanation:

\frac{1}{3}x - 4 = \frac{3}{4} x+ 1

To remove the denominator we take LCD

LCD of 3  and 4  is 12

In the second step we multiply the whole equation by 12 not only the fractions

12*\frac{1}{3}x - 4*12= \frac{3}{4} x*12+ 1*12

Now the denominator gets removed

1/3 * 12 = 4 , also 3/4 times 12 = 3*3 = 9

4x - 48 = 9x + 12

Subtract 9x on both sides

-5x - 48 = 12

Now add 48 on both sides

-5 x = 60

Divide both sides by -5

so x= -12

The value of x= -12

4 0
3 years ago
J is between H and K. If HJ = 2x + 5, JK = 3x - 7, and KH = 18, find the value of x
irina1246 [14]

We know that HJ + JK = HK

So lets substitute each part for their equation.

(2x + 5) + (3x - 7) = 18

Combine like terms

5x -2 = 18

Add 2 to both sides to eliminate it

5x = 20

Divide both sides by 5

x = 4

Let me know if you have any questions about this! :)

4 0
4 years ago
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