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topjm [15]
3 years ago
11

How do I solve

a ) = .8325" alt=" \sin( a ) = .8325" align="absmiddle" class="latex-formula">

It says "Round to the nearest tenth."​
Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

a=56.4\degree

Step-by-step explanation:

Let a be an acute angle.

To solve: \sin(a)=0.8325, we take the sine inverse of both sides to obtain:

\sin^{-1}(\sin(a))=\sin^{-1}(0.8325)

Recall  composition property of a function and its inverse function.

f^{-1}(f(x))=x

We apply this property to the left hand side to obtain;

a=\sin^{-1}(0.8325)

We now use our scientific calculator to obtain;

a=56.3564115\degree

We round to the nearest tenth to obtain;

a=56.4\degree

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Dividing circumference with radius
uranmaximum [27]

If you divide the circumference C over the radius r, you get 2pi

2pi = C/r

this is because

C = 2pi*r

is one formula to find the circumference. Another formula is

C = pi*d

which works because d = 2r, ie the diameter is twice the radius.

7 0
3 years ago
The top of a table has a length of 7 feet and a width of 5 feet. what is the area of the table top
gladu [14]

Answer:<em> 35ft</em>

Step-by-step explanation:

<em>The area for a rectangle or square is Width times Length (W*L)</em>

<em>So we can take our given measurements and multiply them</em>

<em />5*7=35<em />

7 0
3 years ago
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
Which equations are correct?
Leno4ka [110]

9514 1404 393

Answer:

  C, D

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

__

The correct equations are the last two.

For the first two, the appropriate products are ...

  4c^4(3c^2)=4\cdot3c^{4+2}=12c^6\\\\3b^3(a^2b^4)=3a^2b^{3+4}=3a^2b^7

7 0
2 years ago
ASAP<br> Can someone help me with this pleaseeee
Rashid [163]
It’s option D.) I did a quiz on this !
4 0
2 years ago
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