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OLga [1]
3 years ago
11

Equations and Inequalties: Tutorial

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

The number is 4.

Step-by-step explanation:

We can answer the above question as follow:

The square of a number, x is written as: x²

Eight times the number is written as: 8x

From the question, we were told that the square of the number, x is 16 less than eight times the number. This can be written as:

x² = 8x – 16

Rearrange

x² – 8x + 16 = 0

Solving by factorisation method:

Multiply the 1st term (i.e x²) and the last term (i.e 16) together. The result is 16x² as shown below:

x² × 16 = 16x².

Next, find two factors of 16x² such that when we add them together, it will result to the 2nd term ( i.e – 8x).

The factors are –4x and –4x.

Next, replace – 8x in the equation with –4x and –4x. This is illustrated below:

x² – 8x + 16 = 0

x² – 4x – 4x + 16 = 0

Factorise

x(x – 4) – 4(x – 4) = 0

(x – 4)(x – 4) = 0

x – 4 = 0 or x – 4 = 0

x = 4 or x = 4

Thus, the number is 4.

***** Check *****

x² = 8x – 16

x = 4

4² = 8(4) – 16

16 = 32 – 16

16 = 16

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Allisa [31]

9514 1404 393

Answer:

  vertex: (-3, 3)

  focus: (-3, 2)

  directrix: y = 4 (the line)

  point on the parabola: (1, -1)

Step-by-step explanation:

The vertex is the extreme point of the parabola. For a parabola opening downward, it is the maximum. Here, that point is labeled (-3, 3).

The focus is a point inside the parabola on the line of symmetry that, together with the directrix, helps define the parabola. Every point on the parabola is the same distance from the focus as it is from the directrix. Here, the point (-3, 2) is the focus.

The directrix is a line outside the parabola that is the same distance from the vertex that the focus is inside. Here, that line is y = 4.

The point on the parabola (1, -1) appears to have no particular significance. It happens to be 5 units distance from both the focus and the directrix.

_____

<em>Additional comment</em>

When you draw a horizontal line through the focus, it intersects the parabola at a point the same distance from the focus as from the directrix. (All points on the parabola have that characteristic. This point just happens to have the same y-coordinate as the focus.) The point you found this way is also on a line through the vertex that has a slope of 1/2 or -1/2.

If you don't know where the focus is for a given parabola, you can always find it using this relationship.

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