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BlackZzzverrR [31]
3 years ago
7

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar

e. Val says the area is 1917.48 m^2. Find the area enclosed by the figure. Use 3.14 for pi. What error might Val have​ made?
Thanks in advance!
Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

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jeka94

Answer:

The correct answer is :

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Step-by-step explanation:

The first step to solve this question is to draw the plane A with the points P and Q lying on it.

We know that given two different points there is only one line that contains this two different points.

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This option is assuming that exist three lines that contain P and Q. This option is also wrong.

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This option is correct. It will be clarify with the drawing I will attach.

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This option is assuming that exist infinite lines that contain P and Q. This option is wrong.

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