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BlackZzzverrR [31]
3 years ago
7

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar

e. Val says the area is 1917.48 m^2. Find the area enclosed by the figure. Use 3.14 for pi. What error might Val have​ made?
Thanks in advance!
Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

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Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1
jek_recluse [69]

Answer:

S_{31}=71.3


Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

U_n=a_1+(n-1)d


We were given that the 9th term is 17.


\Rightarrow 17=a_1+(9-1)(-2.1)


\Rightarrow 17=a_1+(8)\times(-2.1)


\Rightarrow 17=a_1-\frac{84}{5}


\Rightarrow 17+\frac{84}{5}=a_1


\Rightarrow a_1=\frac{169}{5}


The sum of the first n-terms is given by the formula,


S_n=\frac{n}{2}(2a_1+(n-1)d)


To find S_{31}, we substitute n=31, a_1=\frac{169}{5} and d=-2.1.


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))



\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})


\Rightarrow S_{31}=\frac{713}{10}


\Rightarrow S_{31}=71.3


The correct answer is D















8 0
3 years ago
Read 2 more answers
PLEASE HELP ME SEE IF MY ANSWERS ARE CORRECT!!!!!!!
Lena [83]
So first one
'how many solutions does 2x-y=-5 and 2x+y=5 have?'
add and get
2x-y-5
plus
2x+y=5

equals
2x+2x+y-y=5-5
4x=0
x=0 always
solve for y
4(0)+y=5
y=5
the solution is (0,5)
only <u>ONE </u>solution






one way is to subsitute
just remember that it is in (x,y) form so
the pont (1,2) means that 1 solution is x=1 and y=2 so subsitute and find that
the first one is the answer you are correct





just look at the graph
the solution is the intersection
it seems to be at a point that is 3 units to the right and -6 units up (6 units down)
so the solution is (3,-6)
yo are corect








subsitution
y=y
therefor
the answe ris (-4,-14) if you did the math correctly











#8 is correct

# 9 is correct




# 10 the answe ris bananas=0.40 pears=0.60


the  last one you got it wrong, remember to check your answer to the graph for commonsense
then answer is (-2,5) and (1,2)
8 0
3 years ago
Use the graph to determine
Sonja [21]

Answer:

a. Domain : All Real Numbers

b. Range: y≥ -1

c. The x-intercepts are (0,0) and (-4,0)

d. The y-intercept is (0,0).

e. f(2)=3

   f(-2)=-1

Step-by-step explanation:

If this has helped you please mark as brainliest

3 0
3 years ago
In two or more complete sentences describe how to determine the appropriate model for the set of data. (1, 1), (3, 2), (6, 3), (
Dafna1 [17]

Answer:

3,2

Step-by-step explanation:

hope you like it then comment

5 0
3 years ago
-5y - 6bStep 1 of 2: Identify the first term of the algebraic expression. Indicate whether theterm is a variable term or a const
ira [324]

Answer:

a. Variable term

b. Variable term

Explanation:

a) We were given the algebraic expression:

-5y-6b

The first term of the algebraic expression is:

-5y

The first term is a variable term

The variable is "y" and its coefficient is "-5"

b) We were given the algebraic expression:

-5y-6b

The second term of the algebraic expression is:

-6b

The second term is a variable term

The variable is "b" and the coefficient is "-6"

6 0
1 year ago
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