Question

Which ordered pairs are solutions to the inequality x+3y≥−8?

Answer 1

Answer:

(−6, 0) , (−1, −2)  and (−5, −1)

Step-by-step explanation:

The given inequality is  x+3y ≥ −8

Substitute all the given points in this inequality and check which points satisfy.

For (−6, 0)

-6+3(0) ≥ −8

- 6 + 0  ≥ −8

- 6 ≥ −8   => True.

Hence, (−6, 0) is a solution.

For (−1, −2)

-1 + 3(-2) ≥ −8

-1 - 6 ≥ −8

- 7 ≥ −8 => True.

Hence, (−1, −2) is a solution.

For (−5, −1)

-5 + 3 (-1) ≥ −8

- 5 -3  ≥ −8

-8 ≥ −8=> True.

Hence, (−5, −1) is a solution.

For (−16, 2)

-16 +3 (2) ≥ −8

-16 + 6 ≥ −8

-10≥ −8 => False.

Hence,(−16, 2) is not a solution.

For (0, -3)

0 + 3(-3) ≥ −8

-9  ≥ −8=> False.

Hence, (0, -3) is not a solution.

Therefore, below ordered pairs are solutions of the given inequality

(−6, 0) , (−1, −2)  and (−5, −1)

Answer 2

(-6,0)
(-1,-2)
(-5,-1)