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Alenkasestr [34]
3 years ago
10

Find the difference. Simplify. Combine Like Terms.

Mathematics
1 answer:
Ivan3 years ago
5 0

Answer:

\huge{ \fbox{ \sf{ - 2y - 30}}}

Step-by-step explanation:

\star{ \sf{ \: (4y - 10) - (6y + 20)}}

\text{Step \: 1 }\:  :  \sf{While \: subtracting \: sign \: of \: each \: term \: of \: the \: second \: expression \: changes}

\hookrightarrow{ \sf{4y - 10 - 6y - 20}}

\text{Step \: 2 \:  :  \sf Collect \: like \: terms}

\sf{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\hookrightarrow{ \sf{4y - 6y - 10 - 20}}

\hookrightarrow{ \sf{ - 2y - 10 - 20}}

\text{Step \: 3 \:  :  \sf{Calculate}}

\underline{ \text{Remember!}}  :  \sf{The \: negative \: integers \: are \:always \: added \: but \: posses \: the \: negative \: ( - ) \: sign.}

\hookrightarrow{ \sf{ - 2y - 30}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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Answer:

153.86.

Step-by-step explanation:

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Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand
SOVA2 [1]

Answer:

<u>Question 1:</u>

<u>(a) </u>P(x<60) = 0.9236

<u>(b) </u>P(x>16) = 0.9564

<u>(c) </u>P(16<x<60) = 0.88

<u>(d) </u>P (x>60) = 0.0764

<u />

<u>Question 2:</u>

<u>(a) </u>P(x<3) = 0.0668

<u>(b) </u>P(x>7) = 0.0062

<u>(c) </u>P(3<x<7) = 0.927

<u />

Step-by-step explanation:

<u>Question 1:</u>

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

             = P(z < 20/14)

             = P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

                 = P(z>-1.71)

                 = 1 - P(z<-1.71)

                 = 1 - 0.0436

    P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

                        = P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

                                         P(16<x<60) = 0.9236 - 0.0436

                                         P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

     we have calculated P(x<60) in part (a) so,

    P(x>60) = 1 - 0.9236

    P (x>60) = 0.0764

<u>Question 2:</u>                              

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

                = P(z<-1.5)

     P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

               = 1 - P(z<(7-4.5)/1)

               = 1 - P(z<2.5)

               = 1 - 0.9938

    P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

  we have computed both of these probabilities in parts (a) and (b) so,

    P(3<x<7) = 0.9938 - 0.0668

    P(3<x<7) = 0.927

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